
Which among the following has the highest ionic radius?
A. \[{F^ - }\]
B. \[{B^{ + 3}}\]
C. \[{O_2}^{ - 2}\]
D. \[L{i^ + }\]
Answer
539.1k+ views
Hint: Initially you should be aware of the radius of the ion Is calculated. Also, you must be aware of the ionic radius. You must know that it is the number of electrons which commands the ionic radius.
Complete step by step answer:
The ionic radius is not a fixed property of any given ion. Rather, it varies with coordination number, spin state, and other parameters. For our purposes, we are considering the ions to be as close to their ground state as possible. Nevertheless, ionic radius values are sufficiently transferable to allow periodic trends to be recognized
\[{F^ - }\] and \[{O_2}^{ - 2}\] are isoelectronic species possessing 10 electrons each.
\[L{i^ + }\] and \[{B^{ + 3}}\] are isoelectronic species possessing 2 electrons each.
Since in the case of \[{O_2}^{ - 2}\] , there is greater electron-electron repulsion and lesser effective nuclear charge, \[{O_2}^{ - 2}\] has the largest ionic radius in this case.
So, the correct answer is Option C.
Note: Oxygen is just too chemically reactive to stay a free element in air without being continuously replenished by the photosynthetic action of living organisms. In a space lattice, the ionic radius may be a measure of the dimensions of the atom's ion.6 When formed, ionic atoms change in size with reference to their original atom. Cation radii will decrease and therefore the anion radii will increase in size compared to their neutral atoms.
Complete step by step answer:
The ionic radius is not a fixed property of any given ion. Rather, it varies with coordination number, spin state, and other parameters. For our purposes, we are considering the ions to be as close to their ground state as possible. Nevertheless, ionic radius values are sufficiently transferable to allow periodic trends to be recognized
\[{F^ - }\] and \[{O_2}^{ - 2}\] are isoelectronic species possessing 10 electrons each.
\[L{i^ + }\] and \[{B^{ + 3}}\] are isoelectronic species possessing 2 electrons each.
Since in the case of \[{O_2}^{ - 2}\] , there is greater electron-electron repulsion and lesser effective nuclear charge, \[{O_2}^{ - 2}\] has the largest ionic radius in this case.
So, the correct answer is Option C.
Note: Oxygen is just too chemically reactive to stay a free element in air without being continuously replenished by the photosynthetic action of living organisms. In a space lattice, the ionic radius may be a measure of the dimensions of the atom's ion.6 When formed, ionic atoms change in size with reference to their original atom. Cation radii will decrease and therefore the anion radii will increase in size compared to their neutral atoms.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

