Question

What number is $25\% $ of $64$?

Answer 1

Hint: In the given question, we are required to calculate a specific percentage of the number when the whole quantity is provided. We must remember the formula for finding a specific percentage of a number as: $\text{Percentage} = \dfrac{\text{Part}}{\text{Whole}} \times 100\% $. Percentage of a number corresponds to the share or share in the whole thing.

Complete step by step answer:
In this specific question, we are required to find $25\% $ of the number given to us, $64$.So, we find the number that corresponds to $25\% $ of $64$ by using the formula for percentage as $\text{Percentage} = \dfrac{\text{Part}}{\text{Whole}} \times 100\% $.Let us assume $25\% $ of $64$ to be equal to $x$. So, the whole corresponds to the number $64$ and the part corresponds to the number x in this case. Also, the percentage is given to us as $25\% $. So, we substitute these known values in the above mentioned formula. So, we get,
$ \Rightarrow 25\% = \dfrac{x}{{64}} \times 100\% $

Now, we have to find the value of x in the above equation. We use the method of transposition to shift the terms in the equation and find the value of the variable. Keeping the variable on right side of equation and constants to the left side of the equation, we get,
\[ \Rightarrow 25\% \times \dfrac{{64}}{{100\% }} = x\]
Simplifying the calculations, we get,
\[ \Rightarrow x = 25\% \times \dfrac{{64}}{{100\% }}\]
Simplifying the calculations by cancelling common factors in numerator and denominator, we get,
\[ \Rightarrow x = 1 \times \dfrac{{64}}{4}\]
\[ \therefore x = 16\]
So, the value of $x$ is $16$.

Hence, $16$ is $25\% $ of $64$.

Note:The percentage formula $\text{Percentage} = \dfrac{\text{Part}}{\text{Whole}} \times 100\% $ can be used to find any parameter in the equation given the other parameters. In the question, we must mind the language and substitute the values of the known parameters at the right place to get to the required answer. The final answer must be given in the whole number quantity by cancelling the common factors in numerator and denominator.