What is the unit of molar conductance?
Answer
549.9k+ views
Hint: To know the unit of molar conductance, we should go through the whole concept or the explanation of molar conductance and the conductivity. And on the basis of its definition, we will come to know the unit.
Complete step by step answer:
When one mole of an electrolyte is dissolved in a solution, the ions produced in the solution are capable of conducting electricity. Molar conductance is defined as the conducting power of the dissolved ions produced in the solution.
Molar conductance is denoted by $\lambda $ (lambda) and its unit is given by $S\,c{m^2}\,mo{l^{ - 1}}$ .
Now, the relation between molar conductance and specific conductance denoted as $(k)$ is given by-
$\lambda = kM$
here $M$ is the Molar concentration of the number of moles of solute per litre solution.
$ = k \times 1000M$ (The unit of $M$ is expressed in molarity i.e. $mol\,{L^{ - 1}}$ )
We know the unit of specific conductance $k$ is $S\,c{m^{ - 1}}$ .
$
\therefore \lambda = S\,c{m^{ - 1}} \times c{m^3}\,mo{l^{ - 1}} \\
= S\,c{m^2}mo{l^{ - 1}} \\
$
Note: In general, the molar conductivity of an electrolytic solution is the conductance of the volume of the solution containing a unit mole of electrolyte that is placed between two electrodes of unit area cross-section or at a distance of one-centimetre apart.
Complete step by step answer:
When one mole of an electrolyte is dissolved in a solution, the ions produced in the solution are capable of conducting electricity. Molar conductance is defined as the conducting power of the dissolved ions produced in the solution.
Molar conductance is denoted by $\lambda $ (lambda) and its unit is given by $S\,c{m^2}\,mo{l^{ - 1}}$ .
Now, the relation between molar conductance and specific conductance denoted as $(k)$ is given by-
$\lambda = kM$
here $M$ is the Molar concentration of the number of moles of solute per litre solution.
$ = k \times 1000M$ (The unit of $M$ is expressed in molarity i.e. $mol\,{L^{ - 1}}$ )
We know the unit of specific conductance $k$ is $S\,c{m^{ - 1}}$ .
$
\therefore \lambda = S\,c{m^{ - 1}} \times c{m^3}\,mo{l^{ - 1}} \\
= S\,c{m^2}mo{l^{ - 1}} \\
$
Note: In general, the molar conductivity of an electrolytic solution is the conductance of the volume of the solution containing a unit mole of electrolyte that is placed between two electrodes of unit area cross-section or at a distance of one-centimetre apart.
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