Question

What is the name of $PbHP{{O}_{4}}$ ?

Answer 1

Hint: While writing the name of an ionic compound we are supposed to write the cation name first and later anion name should be written. Identification of the cationic part and anionic part is crucial while writing the name for an ionic compound

Complete answer:
- In the question it is asked to write the name of $PbHP{{O}_{4}}$ .
- We have to identify if the given compound is ionic or not.
- We know that the given compound $PbHP{{O}_{4}}$ is ionic in nature.
- The common name of the salts can be written as Metal (charge) anion.
- Now in the given chemical the metal is lead (Pb) in the form of $P{{b}^{+2}}$ and the anion is $HPO_{4}^{-2}$ .
- Means the oxidation state of lead is +2.
- After dissolving in water the chemical $PbHP{{O}_{4}}$ is going to split in the following way.
$PbHP{{O}_{4}}\to P{{b}^{2+}}+HPO_{4}^{-2}$
- From the above chemical equation we can say that the oxidation number of the lead in $PbHP{{O}_{4}}$ is +2.
- Therefore the chemical name is lead (II) hydrogen phosphate.
- The chemical name of $P{{b}_{2}}{{(HP{{O}_{4}})}_{4}}$ is different form the chemical name of the $PbHP{{O}_{4}}$ .
- The chemical name of $P{{b}_{2}}{{(HP{{O}_{4}})}_{4}}$ is lead (IV) hydrogen phosphate.


Note:
The oxidation state of the cation part is supposed to be represented in roman numerals in brackets after the name of the cation in the chemical name of the compound. In the given chemical roman number (II) gives the information about the oxidation state of the Lead.