Question

What is the mass of \[Cl\] in \[21g\] of \[NaCl\] ?

Answer 1

Hint: We can know that mass is the quantitative proportion of dormancy, a major property of all matter. It is in actuality, the opposition that a collection of issues offers to an adjustment of its speed or position upon the utilization of a power. The more noteworthy the mass of a body, the more modest the change created by an applied power.

Complete step by step answer:
First, we have to find the number of moles of sodium chloride. The atomic mass of sodium is $23g/mol$ and the atomic mass of chlorine is $35.5g/mol$. Then, the total molar mass of sodium chloride is $58.5g/mol$. We have to know the given mass of sodium chloride is $21g$. Now, we have to applying the above values in the following formula,
$Mole = mass \times molar mass$

$Mole = 21g \times \dfrac{{1mol}}{{58.5g}} = 0.36mol$

Now, we have to find the mole of sodium chloride, that is $0.36mol$.
One mole of $NaCl$ consists of one mol of sodium ion and one mole of chloride ion.
The balanced chemical equation of $NaCl$ has to be given,
$NaCl \to N{a^ + } + C{l^ - }$
We have to know the $0.36mol$ of $NaCl$ is equal to the $0.36mol$of $Cl$,
Finally, we have to calculate the mass of $Cl$ by using the following formula,
$Mass = mole \times atomic mass$
$Mass = 0.36mol \times \dfrac{{35g}}{{1mol}} = 12.78g$

Hence, the mass of $Cl$ is $12.78g$.

Note: As we know that the sodium chloride, otherwise called table salt, is an ionic compound made out of sodium cations
$N{a^ + }$ and chloride anions $C{l^ - }$ that has the recipe unit $NaCl$.
The molar mass of an ionic compound mentions to you what the mass of one mole of equation units of that separate compound is; you realize that sodium chloride's equation unit contains one sodium particle and one chlorine atom. This implies that sodium chloride's molar mass will be the amount of the molar masses of those two atoms.