What is the LCM of 6 and 7?
Answer
592.8k+ views
Hint: To calculate the LCM of two numbers, we should first find the prime factorisation of both numbers, and then, we can write LCM by multiplying the prime factors as many times as the maximum number of times of their occurrence in any given number.
Complete step by step solution:
Least Common Multiple or LCM of two numbers, a and b, is defined as the smallest number possible that is perfectly divisible by both a and b.
To use prime factorisation method, we first calculate the prime factorisation, and then list the prime factors as many times as the maximum number of times of their occurrence.
Here in this question, we need to calculate the LCM of 6 and 7.
Prime factorisation of 6:
\[\begin{align}
& 2\left| \!{\underline {\,
6 \,}} \right. \\
& 3\left| \!{\underline {\,
3 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}\]
$\therefore 6=2\times 3$
Prime factorisation of 7:
$\begin{align}
& 7\left| \!{\underline {\,
7 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}$
$\therefore 7=7\times 1$
Now, for the prime factor 2, we have,
The number of times of occurrence of 2 in prime factorisation of 6 = 1
The number of times of occurrence of 2 in prime factorisation of 7 = 0
So, the maximum number of times of occurrence of 2 = 1 …(i)
Similarly, for the prime factor 3, we have,
The number of times of occurrence of 3 in prime factorisation of 6 = 1
The number of times of occurrence of 3 in prime factorisation of 7 = 0
So, the maximum number of times of occurrence of 3 = 1 …(ii)
Similarly, for the prime factor 7, we have,
The number of times of occurrence of 7 in prime factorisation of 6 = 0
The number of times of occurrence of 7 in prime factorisation of 7 = 1
So, the maximum number of times of occurrence of 7 = 1 …(iii)
Now using (i), (ii) and (iii), we can say that 2 must occur once, 3 must also occur once, and 7 must also occur once. Thus,
$LCM=2\times 3\times 7$
$\Rightarrow LCM=42$
Hence, the LCM of 6 and 7 is 42.
Note: Here, we can notice that the two numbers 6 and 7 do not have a common factor other than 1. In such a case, the LCM will always be equal to the product of the two numbers, i.e., $LCM=6\times 7=42$ .
Complete step by step solution:
Least Common Multiple or LCM of two numbers, a and b, is defined as the smallest number possible that is perfectly divisible by both a and b.
To use prime factorisation method, we first calculate the prime factorisation, and then list the prime factors as many times as the maximum number of times of their occurrence.
Here in this question, we need to calculate the LCM of 6 and 7.
Prime factorisation of 6:
\[\begin{align}
& 2\left| \!{\underline {\,
6 \,}} \right. \\
& 3\left| \!{\underline {\,
3 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}\]
$\therefore 6=2\times 3$
Prime factorisation of 7:
$\begin{align}
& 7\left| \!{\underline {\,
7 \,}} \right. \\
& \text{ }\left| \!{\underline {\,
1 \,}} \right. \\
\end{align}$
$\therefore 7=7\times 1$
Now, for the prime factor 2, we have,
The number of times of occurrence of 2 in prime factorisation of 6 = 1
The number of times of occurrence of 2 in prime factorisation of 7 = 0
So, the maximum number of times of occurrence of 2 = 1 …(i)
Similarly, for the prime factor 3, we have,
The number of times of occurrence of 3 in prime factorisation of 6 = 1
The number of times of occurrence of 3 in prime factorisation of 7 = 0
So, the maximum number of times of occurrence of 3 = 1 …(ii)
Similarly, for the prime factor 7, we have,
The number of times of occurrence of 7 in prime factorisation of 6 = 0
The number of times of occurrence of 7 in prime factorisation of 7 = 1
So, the maximum number of times of occurrence of 7 = 1 …(iii)
Now using (i), (ii) and (iii), we can say that 2 must occur once, 3 must also occur once, and 7 must also occur once. Thus,
$LCM=2\times 3\times 7$
$\Rightarrow LCM=42$
Hence, the LCM of 6 and 7 is 42.
Note: Here, we can notice that the two numbers 6 and 7 do not have a common factor other than 1. In such a case, the LCM will always be equal to the product of the two numbers, i.e., $LCM=6\times 7=42$ .
Recently Updated Pages
Guru Purnima speech in English in 100 words class 7 english CBSE

Master Class 7 Science: Engaging Questions & Answers for Success

Master Class 7 English: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Trending doubts
List of coprime numbers from 1 to 100 class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

The plural of Chief is Chieves A True B False class 7 english CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE


