Question

What is the IUPAC name of ${{H}_{2}}[PtC{{l}_{6}}]$?

Answer 1

Hint: A coordination compound is one that has two atoms that are in close proximity to one another. The oxidation state of coordination compounds is also stated in the IUPAC name, along with the central metal atom in roman form. The state of platinum's oxidation in ${{H}_{2}}[PtC{{l}_{6}}]$ is 4.

Complete answer:
When it comes to naming coordination compounds, there are certain guidelines to follow.
The following is a step-by-step procedure for naming the coordination compound:
The positive ion is called first, followed by the anion. The difficult part is written in a single word. The name is written without the hyphen and the numerical prefixes used to denote the number of ligands are di for 2, tri for 3, tetra for 4, Penta for 5, Hexa for 6.
The ligands were positive, negative, or neutral, and they were called in alphabetical order.
The ligand is named first in the complex, followed by the name of the central metal atom.
If the complex is a cation, write the ligand's name first, followed by the central metal atom's oxidation state in Romans, and finally the anion's name.
If the complex is an anion, write the name of the cation and the name of the ligand first, then add –ate and the oxidation state of the central metal atom.
The given compound in the question is ${{H}_{2}}[PtC{{l}_{6}}]$.
Here the central metal atom is platinum and chloride is the ligand. Hydrogen is the cationic part and the complex is the anionic part. The oxidation number of platinum is:
$+1(2)+x+6(-1)=0$
$2+x-6=0$
$x=6-2=4$
So, the oxidation number is +4.
Therefore, the name of the complex is Dihydrogen hexachloroplatinate(IV).

Note:
Only one ‘m' is used in the naming of amines, but the term ‘ammine' is used for the ligand ammonia ($N{{H}_{3}}$ ). Bis and tris can also be used in place of bi and tri, respectively.