What is the derivative of ${{5}^{x}}$ ?
Answer
545.4k+ views
Hint: To obtain the derivative of ${{5}^{x}}$ we will use logarithm function. Firstly we will let $y={{5}^{x}}$ and then take a logarithm function on both sides of the equation. Next we will use the logarithm property and simplify our equation. Finally we will differentiate the equation with respect to $x$ using implicit differentiation and get the desired answer.
Complete step-by-step answer:
To find the derivative of ${{5}^{x}}$ we will let,
$y={{5}^{x}}$…..$\left( 1 \right)$
Taking $\log $ both sides we get,
$\log \left( y \right)=\log \left( {{5}^{x}} \right)$
Using logarithm property on right hand side which is given as:
$\log \left( {{a}^{b}} \right)=b\log \left( a \right)$
Where $a,b$ can be any constant or variable
We get,
$\log \left( y \right)=x\log \left( 5 \right)$…..$\left( 2 \right)$
Differentiating equation (2) with respect to $x$ using implicit differentiation we get,
$\begin{align}
& \log \left( y \right)=x\log \left( 5 \right) \\
& \Rightarrow \dfrac{1}{y}\times \dfrac{dy}{dx}=\log \left( 5 \right)\times \dfrac{d\left( x \right)}{dx} \\
& \Rightarrow \dfrac{1}{y}\times y=\log \left( 5 \right)\times 1 \\
& \therefore {y}'=y\log \left( 5 \right) \\
\end{align}$
Where, Primes $\left( ' \right)$ denote the differentiation with respect to $x$
Replacing $y$ value from equation (1) in above equation we get,
$\begin{align}
& \Rightarrow {{y}^{'}}={{5}^{x}}\log \left( 5 \right) \\
& \therefore {{\left( {{5}^{x}} \right)}^{'}}={{5}^{x}}\log \left( 5 \right) \\
\end{align}$
Hence, the derivative of ${{5}^{x}}$ is ${{5}^{x}}\log \left( 5 \right)$
Note: An exponential function is expressed as $f\left( x \right)={{a}^{x}}$ where $a$ is a positive real number and $x$ is an argument which is present as an exponent. The growth rate of such a function is directly proportional to the value of the function. Implicit differentiation is done when we can’t find the derivative of $y$ in $x$ term, that is $x$ doesn’t lead to $y$ directly. We can use another method to find the derivative of the exponential function by using the direct formula of it. To find the derivative of ${{5}^{x}}$ we can also use the derivative formula for exponential function as,
The formula is given below:
$\dfrac{d}{dx}{{a}^{x}}={{a}^{x}}{{\log }_{e}}a$….$\left( 3 \right)$ For $a\in R$
On comparing the above equation by ${{5}^{x}}$ we get,
$a=5$
On substituting the above value in equation (3) we get,
$\Rightarrow \dfrac{d}{dx}{{5}^{x}}={{5}^{x}}{{\log }_{e}}5$
Hence, the derivative of ${{5}^{x}}$ is${{5}^{x}}{{\log }_{e}}5$.
Complete step-by-step answer:
To find the derivative of ${{5}^{x}}$ we will let,
$y={{5}^{x}}$…..$\left( 1 \right)$
Taking $\log $ both sides we get,
$\log \left( y \right)=\log \left( {{5}^{x}} \right)$
Using logarithm property on right hand side which is given as:
$\log \left( {{a}^{b}} \right)=b\log \left( a \right)$
Where $a,b$ can be any constant or variable
We get,
$\log \left( y \right)=x\log \left( 5 \right)$…..$\left( 2 \right)$
Differentiating equation (2) with respect to $x$ using implicit differentiation we get,
$\begin{align}
& \log \left( y \right)=x\log \left( 5 \right) \\
& \Rightarrow \dfrac{1}{y}\times \dfrac{dy}{dx}=\log \left( 5 \right)\times \dfrac{d\left( x \right)}{dx} \\
& \Rightarrow \dfrac{1}{y}\times y=\log \left( 5 \right)\times 1 \\
& \therefore {y}'=y\log \left( 5 \right) \\
\end{align}$
Where, Primes $\left( ' \right)$ denote the differentiation with respect to $x$
Replacing $y$ value from equation (1) in above equation we get,
$\begin{align}
& \Rightarrow {{y}^{'}}={{5}^{x}}\log \left( 5 \right) \\
& \therefore {{\left( {{5}^{x}} \right)}^{'}}={{5}^{x}}\log \left( 5 \right) \\
\end{align}$
Hence, the derivative of ${{5}^{x}}$ is ${{5}^{x}}\log \left( 5 \right)$
Note: An exponential function is expressed as $f\left( x \right)={{a}^{x}}$ where $a$ is a positive real number and $x$ is an argument which is present as an exponent. The growth rate of such a function is directly proportional to the value of the function. Implicit differentiation is done when we can’t find the derivative of $y$ in $x$ term, that is $x$ doesn’t lead to $y$ directly. We can use another method to find the derivative of the exponential function by using the direct formula of it. To find the derivative of ${{5}^{x}}$ we can also use the derivative formula for exponential function as,
The formula is given below:
$\dfrac{d}{dx}{{a}^{x}}={{a}^{x}}{{\log }_{e}}a$….$\left( 3 \right)$ For $a\in R$
On comparing the above equation by ${{5}^{x}}$ we get,
$a=5$
On substituting the above value in equation (3) we get,
$\Rightarrow \dfrac{d}{dx}{{5}^{x}}={{5}^{x}}{{\log }_{e}}5$
Hence, the derivative of ${{5}^{x}}$ is${{5}^{x}}{{\log }_{e}}5$.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

