
What is the conjugate of $5$?
Answer
528.9k+ views
Hint: In this problem we need to write the conjugate of the given number. We know that conjugate the term which is produced by changing the sign of binomials mostly in the form of $a+\sqrt{b}$ or $a+bi$. But when we observe the given value, it is not a binomial and does not have two values. So, we will assume the given number as $a+\sqrt{b}$ or $a+bi$ after that we will reverse the sign that means we will place $-$ if the number has $+$ or vice versa to get the conjugate of the number.
Complete step-by-step solution:
Given number is $5$.
We can observe that a given value has only one digit and does not have any imaginary or square root symbols. So, we are going to assume the given number as
$5=5+\sqrt{0}$
We all know that the value of $\sqrt{0}=0$. So, there will be no change in the given value.
We have the positive sign in the number $5+\sqrt{0}$. So, to get the conjugate of the number we are going to replace the positive sign with negative sign in the value $5+\sqrt{0}$, then we will get
$5-\sqrt{0}$
We can use the value $\sqrt{0}=0$ in the above equation, then we will have
$5-\sqrt{0}=5$
Hence the conjugate of the given number $5$ is $5$.
Note: Conjugate the numbers are very useful in simplifying the fractions which are having the root numbers or imaginary numbers as denominators. We will simplify the fraction by multiplying and dividing with conjugate number then applying the algebraic formula $\left( a+b \right)\left( a-b \right)={{a}^{2}}-{{b}^{2}}$.
Complete step-by-step solution:
Given number is $5$.
We can observe that a given value has only one digit and does not have any imaginary or square root symbols. So, we are going to assume the given number as
$5=5+\sqrt{0}$
We all know that the value of $\sqrt{0}=0$. So, there will be no change in the given value.
We have the positive sign in the number $5+\sqrt{0}$. So, to get the conjugate of the number we are going to replace the positive sign with negative sign in the value $5+\sqrt{0}$, then we will get
$5-\sqrt{0}$
We can use the value $\sqrt{0}=0$ in the above equation, then we will have
$5-\sqrt{0}=5$
Hence the conjugate of the given number $5$ is $5$.
Note: Conjugate the numbers are very useful in simplifying the fractions which are having the root numbers or imaginary numbers as denominators. We will simplify the fraction by multiplying and dividing with conjugate number then applying the algebraic formula $\left( a+b \right)\left( a-b \right)={{a}^{2}}-{{b}^{2}}$.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

