Question

What is $\dfrac{1}{4}+\dfrac{3}{8}$?

Answer 1

Hint: Here we have to find the sum of two fractions numbers. A fraction represents a numerical value, which defines the parts of a whole. We represent a fraction in the form of $\dfrac{a}{b}$ where a and have no common factor and b is always a non zero quantity. Before adding or subtracting any fractions, we should make sure that the denominators are equal. We can only add or subtract fractions when denominators are the same.

Complete step by step solution:
The given fraction is $\dfrac{1}{4}+\dfrac{3}{8}$
Here we have to add these fraction numbers, for this we will follow some steps which are:
1 When the denominator of both the fraction numbers are the same, then adding them becomes easy. Like if we have $\dfrac{1}{3}+\dfrac{2}{3}$ then their addition is$\dfrac{1+2}{3}=\dfrac{3}{3}=1$ .
2 If the denominator of the fraction numbers are different then first we will take LCM of the denominator numbers, and then we simplify it and then we add them.
Now in the given question $\dfrac{1}{4}+\dfrac{3}{8}$ the denominators are different, so first we will take LCM of the$\left( 4,8 \right)$ . The LCM of $\left( 4,8 \right)$ is $8$ . So putting $8$ in denominator, thus we get only one denominator.
$\Rightarrow \dfrac{1}{4}+\dfrac{3}{8}=\dfrac{2+3}{8}=\dfrac{5}{8}$

Hence we get the sum of the given fraction number is $\dfrac{5}{8}$.

Note: Here we can also find the addition of the above given question by using another method.
Since the denominators are different so first we will make them equal. For this first we will find the minimum common multiple of $4$ and $8$ that is $8$.
So we will convert $\dfrac{1}{4}$ in a number with $8$ as a base. For this first we will divide $\dfrac{8}{4}$ which gives $2$ . Now multiply this $2$ with $\dfrac{1}{4}$, then we get,$\dfrac{1\times 2}{4\times 2}=\dfrac{2}{8}$ now by adding this with $\dfrac{3}{8}$, then we get
$\Rightarrow \dfrac{2}{8}+\dfrac{3}{8}=\dfrac{5}{8}$ .