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What is 52 inches in meters?

seo-qna
Last updated date: 22nd Jul 2024
Total views: 348.9k
Views today: 10.48k
Answer
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348.9k+ views
Hint: First of all we will consider the relationship between inch and centimeter given as: - 1 inch = 2.54 centimeters. Now, we will use the unitary method to find the measure of 52 inches in terms of feet. To find the measure of 52 inches in centimeters, we will multiply both the sides with 52. Once the length in centimeters is calculated we will divide this length with 100 to get the measurement in meters.

Complete step by step solution:
Here we are provided with a length of 52 inches and we have to convert it into meters. However, we will first convert it into centimeters. But first we need to know the relation between inch and centimeter for the required conversion.
We know that both inch and centimeter are the units used for the measurement of small lengths or distances between the two points. These units are inter-convertible and related to each other with the relation: - 1 inch = 2.54 centimeters, i.e. 1 inch measures 2.54 centimeters. So, applying the unitary method to find the measure of 52 inches in terms of centimeters by multiplying both the sides with 52, we get,
$\Rightarrow $ 52 inches = $2.54\times 52$ centimeters
$\Rightarrow $ 52 inches = 132.08 centimeters
Now, we know that the relation between meter and centimeter is given as 1 meter = 100 centimeters, so we can say that 1 centimeter = $\dfrac{1}{100}$ meter. Therefore, dividing 132.08 centimeters by 100 we get the length in meter as: -
$\Rightarrow $ 52 inches = $\dfrac{132.08}{100}$ meters
\[\therefore \] 52 inches = 1.3208 meters
Hence, 52 inches is equivalent to 1.3208 meters.

Note: One must remember the relationship between several units of measurement of distance like: inch, feet, millimeter, centimeter, meter, kilometer, miles etc. Note that 1 feet = 304.8 mm = 30.48 cm = 0.3048 m. In the above solution we have applied the basic approach of the unitary method to get the answer as it is the easiest approach for the solution.