
What weight of a metal of equivalent weight \[12\] will give \[0.475g\] of its chloride?
A.\[0.12g\]
B.\[0.24g\]
C.\[0.36g\]
D.\[0.48g\]
Answer
501.6k+ views
Hint: Equivalent weight of an element or compound is the amount of a substance that completely combines or reacts with other substances in the reaction. Equivalent weight of a compound depends upon two factors, molar mass and the valency of the compound.
Complete answer:
Equivalent weight is very commonly used in physical chemistry. It is used in calculation of Normality which is a measure of Concentration. Equivalent weight is calculated by dividing the molar mass of the compound with valency of the compound.
$\Rightarrow$ \[{E_w} = \dfrac{M}{x}\]
Where \[{E_w}\] is the equivalent weight, M is the molar mass and x is the valency of the compound.
Let us assume that the weight of the metal is \[{W_m}\]. Equivalent weight of metal is given and equivalent weight of Chlorine is \[35.5\]. calculating the Equivalent weight of the metal chloride
$\Rightarrow$ \[E = 12 + 35.5\]
we get the equivalent of metal chloride
$\Rightarrow$ \[E = 47.5g\]
Let us write the given values
Equivalent weight of the metal, \[{E_m} = 12g\]
Weight of metal chloride, \[W = 0.475g\]
for calculating the weight of the metal, we will use the expression
$\Rightarrow$ \[\dfrac{{{E_m}}}{E} = \dfrac{{{W_m}}}{W}\]
Substituting the values of Equivalent weight of metal, Equivalent weight of metal chloride and Weight of the metal chloride we get the equation
$\Rightarrow$ \[{W_m} = \dfrac{{12 \times 0.475}}{{47.5}}\]
The value of weight of the metal is
$\Rightarrow$ \[{W_m} = 0.12g\]
So, the right answer is option (A).
Note:
Valency of different compounds is calculated differently, for acids the valency is given by their basicity, for bases the valency is given by their acidity. The valency of the metal salts is given by the charge on the cation in the compound.
Complete answer:
Equivalent weight is very commonly used in physical chemistry. It is used in calculation of Normality which is a measure of Concentration. Equivalent weight is calculated by dividing the molar mass of the compound with valency of the compound.
$\Rightarrow$ \[{E_w} = \dfrac{M}{x}\]
Where \[{E_w}\] is the equivalent weight, M is the molar mass and x is the valency of the compound.
Let us assume that the weight of the metal is \[{W_m}\]. Equivalent weight of metal is given and equivalent weight of Chlorine is \[35.5\]. calculating the Equivalent weight of the metal chloride
$\Rightarrow$ \[E = 12 + 35.5\]
we get the equivalent of metal chloride
$\Rightarrow$ \[E = 47.5g\]
Let us write the given values
Equivalent weight of the metal, \[{E_m} = 12g\]
Weight of metal chloride, \[W = 0.475g\]
for calculating the weight of the metal, we will use the expression
$\Rightarrow$ \[\dfrac{{{E_m}}}{E} = \dfrac{{{W_m}}}{W}\]
Substituting the values of Equivalent weight of metal, Equivalent weight of metal chloride and Weight of the metal chloride we get the equation
$\Rightarrow$ \[{W_m} = \dfrac{{12 \times 0.475}}{{47.5}}\]
The value of weight of the metal is
$\Rightarrow$ \[{W_m} = 0.12g\]
So, the right answer is option (A).
Note:
Valency of different compounds is calculated differently, for acids the valency is given by their basicity, for bases the valency is given by their acidity. The valency of the metal salts is given by the charge on the cation in the compound.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

