
Volume strength of ${H_2}{O_2}$ is 5.6 its normality will be
Answer
590.4k+ views
Hint: Concentration of a solution is measured by normality. It is denoted by the symbol ‘N’. Normality of a base can be calculated by the below formula.
${\text{Normality}} = {\text{Molarity}} \times {\text{Basicity}}$
Normality of an acid can be calculated by using the given formula.
${\text{Normality}} = {\text{Molarity}} \times {\text{Acidity}}$
Complete step by step answer:
The relationship between volume strength and normality is as follows:
${\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}}$
Given volume strength of ${H_2}{O_2}$is 5.6
$
{\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}} \\
= \dfrac{{5.6}}{{5.6}} \\
= 1\,{\text{N}} \\
$
Hence, the normality of ${H_2}{O_2}$is $1\,{\text{N}}$.
Additional Information:
The formula which is used to calculate normality is-${\text{Normality}} = {\text{Number}}\,{\text{of}}\,{\text{gram}}\,{\text{equivalents}} \times {\left[ {{\text{volume}}\,{\text{of}}\,{\text{solution}}\,{\text{in}}\,{\text{litres}}} \right]^{ - 1}}$
Steps involved in the calculation of normality are discussed below.
Step 1: In this step, we need to gather the information about the equivalent weight of the solute or reacting substance.
Step 2: Number of gram equivalent of solute are calculated in this step.
Step 3: The necessary information to be remembered that the volume is to be calculated by litres.
Step 4: Normality is calculated by substituting the values in the given formula.
We know that normality is mostly used in acid-base theory for determining concentration. In a solution it is used to indicate concentration of ${H_3}{O^ + }$ or $O{H^ - }$ ion. In precipitation reactions the number of ions precipitated for a specific reaction is determined by using normality. Number of losing or gaining electrons by an oxidizing or reducing agent is determined by normality.
Note:
Students might get confused between normality and molarity. Normality is the measure of gram equivalent per litre of solution while molarity is the moles per litre of solution.
${\text{Normality}} = {\text{Molarity}} \times {\text{Basicity}}$
Normality of an acid can be calculated by using the given formula.
${\text{Normality}} = {\text{Molarity}} \times {\text{Acidity}}$
Complete step by step answer:
The relationship between volume strength and normality is as follows:
${\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}}$
Given volume strength of ${H_2}{O_2}$is 5.6
$
{\text{Normality}} = \dfrac{{{\text{Volume strength of }}{H_2}{O_2}}}{{5.6}} \\
= \dfrac{{5.6}}{{5.6}} \\
= 1\,{\text{N}} \\
$
Hence, the normality of ${H_2}{O_2}$is $1\,{\text{N}}$.
Additional Information:
The formula which is used to calculate normality is-${\text{Normality}} = {\text{Number}}\,{\text{of}}\,{\text{gram}}\,{\text{equivalents}} \times {\left[ {{\text{volume}}\,{\text{of}}\,{\text{solution}}\,{\text{in}}\,{\text{litres}}} \right]^{ - 1}}$
Steps involved in the calculation of normality are discussed below.
Step 1: In this step, we need to gather the information about the equivalent weight of the solute or reacting substance.
Step 2: Number of gram equivalent of solute are calculated in this step.
Step 3: The necessary information to be remembered that the volume is to be calculated by litres.
Step 4: Normality is calculated by substituting the values in the given formula.
We know that normality is mostly used in acid-base theory for determining concentration. In a solution it is used to indicate concentration of ${H_3}{O^ + }$ or $O{H^ - }$ ion. In precipitation reactions the number of ions precipitated for a specific reaction is determined by using normality. Number of losing or gaining electrons by an oxidizing or reducing agent is determined by normality.
Note:
Students might get confused between normality and molarity. Normality is the measure of gram equivalent per litre of solution while molarity is the moles per litre of solution.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

