Answer

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**Hint:**

This is a volume related problem. We are given a cuboid with its dimensions in the form of x and y with relations between the length, breadth and height. We are going to use the formula we generally use to find the volume of cuboid.

Volume of cuboid= \[length \times breadth \times height \Rightarrow lbh\]

**Complete step by step solution:**

Given that a cuboid has,

\[breadth(b) = 6{y^2}\]

\[length(l) = 2{x^2} \times breadth = 2{x^2} \times 6{y^2} = 12{x^2}{y^2}\]

\[height(h) = \dfrac{3}{2}xy \times length = \dfrac{3}{2}xy \times 12{x^2}{y^2} = 18{x^3}{y^3}\]

Now we have all the dimensions with us. Let’s find the volume.

Volume of cuboid= \[length \times breadth \times height \Rightarrow lbh\]

Putting the values we get

\[ \Rightarrow 12{x^2}{y^2} \times 6{y^2} \times 18{x^3}{y^3}\]

Now taking constant terms on one side

\[ \Rightarrow 12 \times 6 \times 18 \times {x^2}{y^2} \times {y^2} \times {x^3}{y^3}\]

\[

\Rightarrow 1296{x^{2 + 3}}{y^{2 + 2 + 3}} \to \left( {{a^m}{a^n} = {a^{m + n}}} \right) \\

\Rightarrow 1296{x^5}{y^7} \\

\]

**Thus this is the volume of the cuboid \[ \Rightarrow 1296{x^5}{y^7}\].**

**Note:**

In this problem we may lose the marks just because we have not added the powers of the same base variables like x and y here. Don’t miss that step. Also use the relations given between the dimensions.

Also by mistake we directly take the value of length as \[2{x^2}\] whereas it is \[2{x^2}\] times the breadth. Same for height also. So be attentive.

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