What is the value of ${{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}100 \right) \right]}^{2}}$?
(a) $4$
(b) $3$
(c) $2$
(d) $1$
Answer
601.5k+ views
Hint: In the above question, we have been given a logarithmic expression whose value has to be obtained, which is given as ${{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}100 \right) \right]}^{2}}$. For this, we need to start simplifying the innermost logarithmic term, which is ${{\log }_{10}}100$. This can be simplified by putting $100={{10}^{2}}$ and using the logarithmic property given by ${{\log }_{a}}{{a}^{m}}=m$. Then we will be left with a single logarithmic term which can be simplified similarly. Finally taking the square of the simplified expression obtained, we will be able to obtain the correct answer.
Complete step by step solution:
The expression given in the above question is
$\Rightarrow E={{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}100 \right) \right]}^{2}}$
We start by simplifying the innermost logarithmic term, ${{\log }_{10}}100$. For this, we put $100={{10}^{2}}$ in the above expression to get
$\Rightarrow E={{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}{{10}^{2}} \right) \right]}^{2}}$
Now, by using the property of the logarithmic function given by ${{\log }_{a}}{{a}^{m}}=m$, we can simplify the above expression as
$\begin{align}
& \Rightarrow E={{\left[ {{\log }_{10}}\left( 5\times 2 \right) \right]}^{2}} \\
& \Rightarrow E={{\left[ {{\log }_{10}}10 \right]}^{2}} \\
\end{align}$
Now, we put $10={{10}^{1}}$ in the above expression to get
\[\Rightarrow E={{\left[ {{\log }_{10}}{{10}^{1}} \right]}^{2}}\]
Now, by again using the logarithmic property ${{\log }_{a}}{{a}^{m}}=m$, we can simplify the above expression as
\[\begin{align}
& \Rightarrow E={{\left[ 1 \right]}^{2}} \\
& \Rightarrow E=1 \\
\end{align}\]
Thus, the value of the given logarithmic expression is found to be equal to \[1\].
Hence, the correct answer is option (d).
Note: For solving these types of questions, we have to remember all the important properties of the logarithmic function. We may apply the logarithmic property given by $\log AB=\log A+\log B$ to simplify the given expression as ${{\left[ {{\log }_{10}}5+{{\log }_{10}}100 \right]}^{2}}$. But that will only increase our calculations to get the final answer.
Complete step by step solution:
The expression given in the above question is
$\Rightarrow E={{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}100 \right) \right]}^{2}}$
We start by simplifying the innermost logarithmic term, ${{\log }_{10}}100$. For this, we put $100={{10}^{2}}$ in the above expression to get
$\Rightarrow E={{\left[ {{\log }_{10}}\left( 5{{\log }_{10}}{{10}^{2}} \right) \right]}^{2}}$
Now, by using the property of the logarithmic function given by ${{\log }_{a}}{{a}^{m}}=m$, we can simplify the above expression as
$\begin{align}
& \Rightarrow E={{\left[ {{\log }_{10}}\left( 5\times 2 \right) \right]}^{2}} \\
& \Rightarrow E={{\left[ {{\log }_{10}}10 \right]}^{2}} \\
\end{align}$
Now, we put $10={{10}^{1}}$ in the above expression to get
\[\Rightarrow E={{\left[ {{\log }_{10}}{{10}^{1}} \right]}^{2}}\]
Now, by again using the logarithmic property ${{\log }_{a}}{{a}^{m}}=m$, we can simplify the above expression as
\[\begin{align}
& \Rightarrow E={{\left[ 1 \right]}^{2}} \\
& \Rightarrow E=1 \\
\end{align}\]
Thus, the value of the given logarithmic expression is found to be equal to \[1\].
Hence, the correct answer is option (d).
Note: For solving these types of questions, we have to remember all the important properties of the logarithmic function. We may apply the logarithmic property given by $\log AB=\log A+\log B$ to simplify the given expression as ${{\left[ {{\log }_{10}}5+{{\log }_{10}}100 \right]}^{2}}$. But that will only increase our calculations to get the final answer.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

