Answer

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**Hint:**In 70k the units place is occupied by k . By replacing it with one of our options we need to check the divisibility of the number. With 7 in the place of k , to check the divisibility of 7 multiply the last digit by 2 and subtract it from the number formed by the other two digits. If the difference is 0 or divisible by 7 then the number is divisible by 7.

**Complete step-by-step answer:**Step 1:

In 70k the units place is occupied by k

And we need to value for k such that the number is divisible by 7

Step 2:

We know the divisibility rule of 7

We must choose the last digit of the number and multiply it by 2.

And subtract the product from the rest of the number .

And if the difference is zero or divisible by 7 then the whole number is divisible by 7

Step 3

Now let's consider the number 7 from the options.

So our number will be 707

First we need to multiply the last digit by 2

(i.e) 7*2=14

Now let's subtract 14 from the number formed by the other two digits (i.e.)70

Subtracting 14 from 70 , we get

70 – 14 = 56

Now we know that 56 is divisible by 7

Hence the number 707 is divisible by 7

**The correct option is B.**

**Note:**Many students tend to think 70k as 70*k but in this problem 70k means that the units place is occupied by k

For divisibility of 2 , the units place must be a even number

And for divisibility of 3 , 9 , 11 the sum of the digits must be the multiples of 3 , 9 and 11 respectively.

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