
V vs T curves at different pressure \[{{\text{P}}_1}{\text{ and }}{{\text{P}}_2}\] for an ideal gas shown below. Which one of the following is correct?
A.\[{{\text{P}}_1} > {{\text{P}}_2}\]
B.\[{{\text{P}}_1} < {\text{ }}{{\text{P}}_2}\]
C.\[{{\text{P}}_1} = {\text{ }}{{\text{P}}_2}\]
D.Relation between \[{{\text{P}}_1}{\text{ and }}{{\text{P}}_2}\] depends on the gas.
Answer
563.1k+ views
Hint: With the help of an ideal gas equation we will form a linear equation. Using the value of slope from there we will compare both the pressure.
Formula used:
\[{\text{PV}} = {\text{nRT}}\]
Here P is pressure, V is volume, n is number of moles, R is universal gas constant and T is temperature.
Complete step by step solution:
We have been given the graph between volume and temperature, with volume being on y axis and temperature being on x axis. We can rewrite the ideal gas equation as:
\[{\text{V}} = \dfrac{{{\text{nR}}}}{{\text{P}}}{\text{T}}\]
The general equation for a straight line is \[{\text{y}} = {\text{mx}} + {\text{c}}\]
Here y is the coordinate on y axis, x is the coordinate of x axis, m is the slope and c is the intercept made on y axis. Since in our case the line passes through the origin hence the intercept will be zero.
The equation will reduce to: \[{\text{y}} = {\text{mx}}\]
If we compare this equation to ideal gas equation then we will get y as V and x as T and the slope will be:
\[{\text{m}} = \dfrac{{{\text{nR}}}}{{\text{P}}}\]
According to the above formula slope and pressure are inversely proportional to each other. Now it is clear that the slope of \[{{\text{P}}_1}\] line is more than the slope of \[{{\text{P}}_2}\] . Slope represents tangent of angle. The line \[{{\text{P}}_1}\] makes a greater angle and hence has higher slope. Thus the pressure \[{{\text{P}}_1}\] will be lesser than \[{{\text{P}}_2}\] .
Thus, the correct option is B.
Note:
The ideal gas equation is made up using the basic laws such as Boyle’s law, Charles’ law etc. If we keep the temperature constant the product of pressure and volume will also become constant which signifies Boyle's law. Similarly other laws can be proved.
Formula used:
\[{\text{PV}} = {\text{nRT}}\]
Here P is pressure, V is volume, n is number of moles, R is universal gas constant and T is temperature.
Complete step by step solution:
We have been given the graph between volume and temperature, with volume being on y axis and temperature being on x axis. We can rewrite the ideal gas equation as:
\[{\text{V}} = \dfrac{{{\text{nR}}}}{{\text{P}}}{\text{T}}\]
The general equation for a straight line is \[{\text{y}} = {\text{mx}} + {\text{c}}\]
Here y is the coordinate on y axis, x is the coordinate of x axis, m is the slope and c is the intercept made on y axis. Since in our case the line passes through the origin hence the intercept will be zero.
The equation will reduce to: \[{\text{y}} = {\text{mx}}\]
If we compare this equation to ideal gas equation then we will get y as V and x as T and the slope will be:
\[{\text{m}} = \dfrac{{{\text{nR}}}}{{\text{P}}}\]
According to the above formula slope and pressure are inversely proportional to each other. Now it is clear that the slope of \[{{\text{P}}_1}\] line is more than the slope of \[{{\text{P}}_2}\] . Slope represents tangent of angle. The line \[{{\text{P}}_1}\] makes a greater angle and hence has higher slope. Thus the pressure \[{{\text{P}}_1}\] will be lesser than \[{{\text{P}}_2}\] .
Thus, the correct option is B.
Note:
The ideal gas equation is made up using the basic laws such as Boyle’s law, Charles’ law etc. If we keep the temperature constant the product of pressure and volume will also become constant which signifies Boyle's law. Similarly other laws can be proved.
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