
How do you use the product rule to find the derivative of \[y = x \cdot \ln \left( x \right)\] ?
Answer
522.3k+ views
Hint: In the given question we have to find the derivative of \[y = x \cdot \ln \left( x \right)\] using the product rule. Now for this you should know what the product rule is. So the product rule is used when you have to find the derivative of a product of two or more functions. Here we have mention the product rule formula for two functions which you have to use to find the solution of the given question i.e.
\[\dfrac{d}{{dx}}\left( {u \cdot v} \right) = u\dfrac{d}{{dx}}\left( v \right) + v\dfrac{d}{{dx}}\left( u \right)\]
Here two functions were \[u(x)\] and \[v(x)\]
Now first find what are the two different functions in the given term and then apply the above given rule and find the derivative. And be careful while differentiating different functions.
Complete step by step solution:
In the given question we have to use the product rule to find the derivative of \[y = x \cdot \ln \left( x \right)\] so here we will first find what the two different functions are in the given term and then apply the product rule.
So the two function are \[x\] and \[\ln \left( x \right)\]
Now let use the product formula on these functions i.e.
\[
\dfrac{d}{{dx}}\left( {u \cdot v} \right) = u\dfrac{d}{{dx}}\left( v \right) + v\dfrac{d}{{dx}}\left( u \right) \\
\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {x \cdot \ln x} \right) \;
\]
Now differentiate the following term we with respect to \[x\] we get,
\[
\dfrac{{dy}}{{dx}} = x\left( {\dfrac{1}{x}} \right) + \ln x\left( 1 \right) \\
\dfrac{{dy}}{{dx}} = 1 + \ln x \;
\]
Hence, \[(1 + \ln x)\] this is the required answer of the given question.
So, the correct answer is “ \[(1 + \ln x)\] ”.
Note: Here first of all you should know the differentiations of simple functions learn all the derivatives of basic functions. Now you have to be careful while doing the differentiation because most of the students make mistakes while differentiating the terms. Also be careful while separating different functions available in the given term. You should also search the proof of the product rule.
\[\dfrac{d}{{dx}}\left( {u \cdot v} \right) = u\dfrac{d}{{dx}}\left( v \right) + v\dfrac{d}{{dx}}\left( u \right)\]
Here two functions were \[u(x)\] and \[v(x)\]
Now first find what are the two different functions in the given term and then apply the above given rule and find the derivative. And be careful while differentiating different functions.
Complete step by step solution:
In the given question we have to use the product rule to find the derivative of \[y = x \cdot \ln \left( x \right)\] so here we will first find what the two different functions are in the given term and then apply the product rule.
So the two function are \[x\] and \[\ln \left( x \right)\]
Now let use the product formula on these functions i.e.
\[
\dfrac{d}{{dx}}\left( {u \cdot v} \right) = u\dfrac{d}{{dx}}\left( v \right) + v\dfrac{d}{{dx}}\left( u \right) \\
\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {x \cdot \ln x} \right) \;
\]
Now differentiate the following term we with respect to \[x\] we get,
\[
\dfrac{{dy}}{{dx}} = x\left( {\dfrac{1}{x}} \right) + \ln x\left( 1 \right) \\
\dfrac{{dy}}{{dx}} = 1 + \ln x \;
\]
Hence, \[(1 + \ln x)\] this is the required answer of the given question.
So, the correct answer is “ \[(1 + \ln x)\] ”.
Note: Here first of all you should know the differentiations of simple functions learn all the derivatives of basic functions. Now you have to be careful while doing the differentiation because most of the students make mistakes while differentiating the terms. Also be careful while separating different functions available in the given term. You should also search the proof of the product rule.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

