
How do you use multiplying by 1 to find an expression equivalent to $\dfrac{7}{6}$ with a denominator of $6d$?
Answer
518.4k+ views
Hint: The question here gives us just a basic premise that we can only multiply by $1$ and no other number, and we have to create a denominator of $6d$in the final expression. We will have to use the property of $1$ to achieve the given expression. We know that if both the numerator and the denominator of a fraction is the same then the value of that fraction can be written as equal to $1$ by cancelling both the numerator and the denominator. So use that property to achieve the desired expression.
Complete step by step solution:
The given question will use the property of $1$ that fraction is equal to one if both the numerator and the denominators are equal we will take our numerator and denominator to be $d$
So upon multiplying \[\dfrac{d}{d}\] by our given expression we get,
\[\dfrac{d}{d} \times \dfrac{7}{6}\]
Upon solving we will get
\[\dfrac{{7d}}{{6d}}\]
Which in itself is equal to \[\dfrac{7}{6}\] if we cancel $d$ but we have now fulfilled the basic premise of the question which is that the denominator of the resulting expression must be $6d$.
Note: whenever doing this type of questions we can do the above operation for any given expression that we have to input into the denominator or the numerator for that matter but should always put in our minds to not introduce $0$ anywhere , because on doing so the given expression instead of becoming $1$ becomes undefined and is then not solvable.
Complete step by step solution:
The given question will use the property of $1$ that fraction is equal to one if both the numerator and the denominators are equal we will take our numerator and denominator to be $d$
So upon multiplying \[\dfrac{d}{d}\] by our given expression we get,
\[\dfrac{d}{d} \times \dfrac{7}{6}\]
Upon solving we will get
\[\dfrac{{7d}}{{6d}}\]
Which in itself is equal to \[\dfrac{7}{6}\] if we cancel $d$ but we have now fulfilled the basic premise of the question which is that the denominator of the resulting expression must be $6d$.
Note: whenever doing this type of questions we can do the above operation for any given expression that we have to input into the denominator or the numerator for that matter but should always put in our minds to not introduce $0$ anywhere , because on doing so the given expression instead of becoming $1$ becomes undefined and is then not solvable.
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