
How do you use FOIL to multiply $(x + h)(x + h)$?
Answer
521.1k+ views
Hint: Foil method is an abbreviation to memorize the methods to multiply two binomials.
The full form and its meaning is stated below:
1. F-first terms( To multiply the first terms)
2. O-outer terms(To multiply the outer terms)
3. I-Inner terms(To multiply the inner terms)
4.L-last terms(To multiply the last terms)
For example, $(x + y)(p + q) = xp + xq + yp + yq$
Complete step by step answer:
In the equation $(x + h)(x + h) = F + O + I + L$
$
F = x \times x \\
O = x \times h \\
I = h \times x \\
L = h \times h \\
$
Now, we Substitute these values into the equation
$
(x + h)(x + h) = F + O + I + L \\
(x + h)(x + h) = x \times x + x \times h + h \times x + h \times h \\
(x + h)(x + h) = {x^2} + hx + hx + {h^2} \\
(x + h)(x + h) = {x^2} + 2hx + {h^2} \\
$
Hence, the solution is ${x^2} + 2hx + {h^2}$
Note: We can also use an alternative method to solve the above equation.
We can directly use the formula ${(a + b)^2} = {a^2} + {b^2} + 2ab$
Hence the equation is , ${(x + h)^2} = {x^2} + {h^2} + 2xh$
The full form and its meaning is stated below:
1. F-first terms( To multiply the first terms)
2. O-outer terms(To multiply the outer terms)
3. I-Inner terms(To multiply the inner terms)
4.L-last terms(To multiply the last terms)
For example, $(x + y)(p + q) = xp + xq + yp + yq$
Complete step by step answer:
In the equation $(x + h)(x + h) = F + O + I + L$
$
F = x \times x \\
O = x \times h \\
I = h \times x \\
L = h \times h \\
$
Now, we Substitute these values into the equation
$
(x + h)(x + h) = F + O + I + L \\
(x + h)(x + h) = x \times x + x \times h + h \times x + h \times h \\
(x + h)(x + h) = {x^2} + hx + hx + {h^2} \\
(x + h)(x + h) = {x^2} + 2hx + {h^2} \\
$
Hence, the solution is ${x^2} + 2hx + {h^2}$
Note: We can also use an alternative method to solve the above equation.
We can directly use the formula ${(a + b)^2} = {a^2} + {b^2} + 2ab$
Hence the equation is , ${(x + h)^2} = {x^2} + {h^2} + 2xh$
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