
What is the unit of latent heat of the body?
$\begin{align}
& \text{A}\text{. }\dfrac{\text{Joule}}{\text{kg}} \\
& \text{B}\text{. }\dfrac{\text{Calorie}}{\text{ }\!\!{}^\circ\!\!\text{ C}} \\
& \text{C}\text{. }\dfrac{\text{Joules}}{\text{ }\!\!{}^\circ\!\!\text{ C}} \\
& \text{D}\text{. }\dfrac{\text{kg}}{\text{Joules}} \\
\end{align}$
Answer
581.1k+ views
Hint: When change of states happen (i.e. when a solid changes to liquid or liquid changes to gas), the substance absorbs heat but does not change or increase its temperature. This heat used to change the state is hidden or latent (lies hidden). Latent heat is defined as the amount of heat required to change the state of unit mass of a substance at a constant temperature and pressure.
Formula used:
$Q=mL$ where, $Q=\text{ Heat required}$, $m=\text{mass of substance}$, $L=\ \text{Latent heat}$
Complete step-by-step answer:
Consider a substance of mass m undergoes a change in state at constant temperature. The amount of heat required for this process is $Q=mL$ where, $Q=\text{ Heat required}$, $ L=\ \text{Latent heat}$, $m=\text{mass of substance}$.
So, $L=\dfrac{Q}{m}$
The S.I unit of $Q$ is Joule and of mass is $kg$
So the unit of latent heat is $\dfrac{Joule}{kg}\text{ or }Joule\times k{{g}^{-1}}$
So, the correct answer is “Option A”.
Additional Information: Latent heat of fusion: The amount of heat required to change the state of unit mass of a substance from solid state to liquid state at melting point is called latent heat of fusion or latent heat of melting. It is usually denoted by ${{L}_{f}}$.
Latent heat of evaporation: The amount of heat required to change the state of unit mass of a substance from liquid state to vapour at boiling point is called latent heat of evaporation or latent heat of boiling. It is usually denoted by ${{L}_{v}}$.
Note: Don’t get confused between Latent heat and specific heat. Latent heat is defined as the amount of heat required to change the state of a substance at constant temperature whereas specific heat is defined as the amount of heat required to increase the temperature of a substance by one degree. So
$c=\dfrac{\Delta Q}{M\times \Delta T}$
Where $c=\text{specific heat of substance}$
$\Delta Q=\text{Heat required to change the temperature by }\Delta T$
$M=\text{mass of the substance}$
S.I units of specific heat is $Joule\times k{{g}^{-1}}\times Kelvi{{n}^{-1}}$
Formula used:
$Q=mL$ where, $Q=\text{ Heat required}$, $m=\text{mass of substance}$, $L=\ \text{Latent heat}$
Complete step-by-step answer:
Consider a substance of mass m undergoes a change in state at constant temperature. The amount of heat required for this process is $Q=mL$ where, $Q=\text{ Heat required}$, $ L=\ \text{Latent heat}$, $m=\text{mass of substance}$.
So, $L=\dfrac{Q}{m}$
The S.I unit of $Q$ is Joule and of mass is $kg$
So the unit of latent heat is $\dfrac{Joule}{kg}\text{ or }Joule\times k{{g}^{-1}}$
So, the correct answer is “Option A”.
Additional Information: Latent heat of fusion: The amount of heat required to change the state of unit mass of a substance from solid state to liquid state at melting point is called latent heat of fusion or latent heat of melting. It is usually denoted by ${{L}_{f}}$.
Latent heat of evaporation: The amount of heat required to change the state of unit mass of a substance from liquid state to vapour at boiling point is called latent heat of evaporation or latent heat of boiling. It is usually denoted by ${{L}_{v}}$.
Note: Don’t get confused between Latent heat and specific heat. Latent heat is defined as the amount of heat required to change the state of a substance at constant temperature whereas specific heat is defined as the amount of heat required to increase the temperature of a substance by one degree. So
$c=\dfrac{\Delta Q}{M\times \Delta T}$
Where $c=\text{specific heat of substance}$
$\Delta Q=\text{Heat required to change the temperature by }\Delta T$
$M=\text{mass of the substance}$
S.I units of specific heat is $Joule\times k{{g}^{-1}}\times Kelvi{{n}^{-1}}$
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

