What unit for temperature should be used in an ideal gas law calculation when using the value 0.0821 as the ideal gas law constant? Celsius Centigrade Fahrenheit Kelvin Plis help is a test
Answer
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Hint :The universal gas constant is a constant, so its unit will not change with time. Thus, it becomes easier to identify the unit of temperature from the unit of universal gas constant.
Complete Step By Step Answer:
Here, the universal gas constant has been given, which comes from the formula PV=NRT.
Here,
P=Pressure, V=Volume. N=Number of moles, R=Universal gas constant and T=Temperature.
The value of R (Universal gas constant) has been given, i.e. 0.0821.
The unit of the universal gas constant is \[\dfrac{atm\bullet L}{mol\bullet K}\] , thus the complete value of the universal gas constant will be given as R=0.0821 \[\dfrac{atm\bullet L}{mol\bullet K}\] .
Now, as the unit of temperature used in the universal gas constant is \[K\] , it will seem compatible to use \[K\] as the unit of temperature in the calculation of any problem including universal gas constant.
If you use any unit of temperature other than \[K\] , the value of answer will differ and it the calculation will be wrong. Thus, you have to use \[K\] in every calculation which includes universal gas constant.
Here, \[K\] represents Kelvin, thus the true answer is Kelvin.
Note :
Here it is necessary to note that you must know the unit of universal gas constant. If you don’t know the unit of the universal gas constant, you can’t know the unit of temperature that you should use in the calculation in which you use universal gas constant.
Complete Step By Step Answer:
Here, the universal gas constant has been given, which comes from the formula PV=NRT.
Here,
P=Pressure, V=Volume. N=Number of moles, R=Universal gas constant and T=Temperature.
The value of R (Universal gas constant) has been given, i.e. 0.0821.
The unit of the universal gas constant is \[\dfrac{atm\bullet L}{mol\bullet K}\] , thus the complete value of the universal gas constant will be given as R=0.0821 \[\dfrac{atm\bullet L}{mol\bullet K}\] .
Now, as the unit of temperature used in the universal gas constant is \[K\] , it will seem compatible to use \[K\] as the unit of temperature in the calculation of any problem including universal gas constant.
If you use any unit of temperature other than \[K\] , the value of answer will differ and it the calculation will be wrong. Thus, you have to use \[K\] in every calculation which includes universal gas constant.
Here, \[K\] represents Kelvin, thus the true answer is Kelvin.
Note :
Here it is necessary to note that you must know the unit of universal gas constant. If you don’t know the unit of the universal gas constant, you can’t know the unit of temperature that you should use in the calculation in which you use universal gas constant.
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