Two particles, of masses M and 2M, moving, as shown, with speeds of 10m/s and 5m/s, collide elastically at the origin. After the collision, they move along the indicated directions with speeds ${v_1}$ and ${v_2}$ respectively. The values of ${v_1}$ and ${v_2}$ are nearly?
Answer
641.7k+ views
Hint: During the collision of particles having certain masses, law of conservation of mass is used. In this question, we find a relation between the masses and the velocity of the particle. Putting the given values in the expression will give us the required result.
Formula used:
$M \times 10\cos {30} + 2M \times 10\cos {45}$
Complete step by step answer:
To find the velocities of the two particles, we have the following relation. Here, particle A with mass M makes an angle of 30 degree, whereas particle B of mass 2M makes an angle of 45 degree. So, our equation becomes:
$\eqalign{& M \times 10\sin {30} + 2M \times 5\sin {45} \cr
& = 2M \times {v_1}\cos {30} + M{v_2}\cos {45} \cr} $
Now, when we substitute the given values in above equation we get:
$5\sqrt 3 + 5\sqrt 2 = 2{v_1}\dfrac{{\sqrt 3 }}{2} + \dfrac{{{v_2}}}{{\sqrt 2 }}$
Now, after the collision of the two particles, we get the equation as:
$\eqalign{
& 10 \times M\sin {30} - 2M \times 5\sin {45} \cr
& = M{v_2}\sin {45} - 2M{v_1}\sin {30} \cr} $
Substituting the given values in the above equation we get the required velocities as:
$\eqalign{& 5 - 5\sqrt 2 = \dfrac{{{v_2}}}{{\sqrt 2 }} - {v_1} \cr
& \Rightarrow {v_1} = \dfrac{{17.5}}{{2.7}} \approx 6.5m/s \cr
& \therefore {v_2} \approx 6.3m/s \cr} $
Therefore, we get the velocities of the particle having mass M and 2M respectively. We can observe that the velocity of the two particles differ in very low value.
Additional information:
From the law of conservation of mass which says that mass can neither be created nor destroyed in any chemical reactions. Also, it can be defined as the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.
We know that collision means when two objects come in contact with each other for a very short period. Collision is an interaction between two masses for a very short interval where the momentum and energy of the colliding masses changes. Here are two types of collision: first id elastic collision where the energy remains same after interaction or collision and second is inelastic collision where the final energy changes after the collision of the particles or body.
Note:
The resulting mass, energy or velocity after the collision of two particles depends on its direction and magnitude as well. During the solution, one should see that laws of conservation are not violated, i.e., mass can neither be created nor be destroyed and similarly for energy of the particles as well.
Formula used:
$M \times 10\cos {30} + 2M \times 10\cos {45}$
Complete step by step answer:
To find the velocities of the two particles, we have the following relation. Here, particle A with mass M makes an angle of 30 degree, whereas particle B of mass 2M makes an angle of 45 degree. So, our equation becomes:
$\eqalign{& M \times 10\sin {30} + 2M \times 5\sin {45} \cr
& = 2M \times {v_1}\cos {30} + M{v_2}\cos {45} \cr} $
Now, when we substitute the given values in above equation we get:
$5\sqrt 3 + 5\sqrt 2 = 2{v_1}\dfrac{{\sqrt 3 }}{2} + \dfrac{{{v_2}}}{{\sqrt 2 }}$
Now, after the collision of the two particles, we get the equation as:
$\eqalign{
& 10 \times M\sin {30} - 2M \times 5\sin {45} \cr
& = M{v_2}\sin {45} - 2M{v_1}\sin {30} \cr} $
Substituting the given values in the above equation we get the required velocities as:
$\eqalign{& 5 - 5\sqrt 2 = \dfrac{{{v_2}}}{{\sqrt 2 }} - {v_1} \cr
& \Rightarrow {v_1} = \dfrac{{17.5}}{{2.7}} \approx 6.5m/s \cr
& \therefore {v_2} \approx 6.3m/s \cr} $
Therefore, we get the velocities of the particle having mass M and 2M respectively. We can observe that the velocity of the two particles differ in very low value.
Additional information:
From the law of conservation of mass which says that mass can neither be created nor destroyed in any chemical reactions. Also, it can be defined as the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.
We know that collision means when two objects come in contact with each other for a very short period. Collision is an interaction between two masses for a very short interval where the momentum and energy of the colliding masses changes. Here are two types of collision: first id elastic collision where the energy remains same after interaction or collision and second is inelastic collision where the final energy changes after the collision of the particles or body.
Note:
The resulting mass, energy or velocity after the collision of two particles depends on its direction and magnitude as well. During the solution, one should see that laws of conservation are not violated, i.e., mass can neither be created nor be destroyed and similarly for energy of the particles as well.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

