Two forces A and B act on an object in the opposite direction. A is bigger than B. The net force on the object is:
A. \[A+B\] acting in the direction of A
B. \[A-B\] acting in the direction of A
C. \[A+B\] acting in the direction of B
D. \[A-B\] acting in the direction of A
E. None of these.
Answer
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Hint: First using the formulas for vector addition calculate the magnitude of the resultant force. As the angle between the two forces is $180{}^\circ $, so the direction of resultant force can be calculated from the vector law’s.
Formula used: If the angle between the resultant force and force A is $\phi$ and the angle between the forces A and B is $\theta$ then the resultant of A and B has magnitude
$\left| \overrightarrow{A}+\overrightarrow{B} \right|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }$
$\tan \phi =\dfrac{A\sin \theta }{A+B\cos \theta }$
Complete step by step answer:
The magnitude of A and B is given by
$\begin{align}
& \left| \overrightarrow{A}+\overrightarrow{B} \right|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta } \\
& =\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos 180} \\
& =\sqrt{{{A}^{2}}+{{B}^{2}}-2AB} \\
& =\sqrt{{{\left( A-B \right)}^{2}}} \\
& =A-B \\
\end{align}$
Consider the angle between the resultant force and the bigger force A is $\phi$. As A and B are in opposite directions then the angle between A and B is $\theta =180{}^\circ $ .
Then
$\begin{align}
& \tan \phi =\dfrac{A\sin \theta }{A+B\cos \theta }=\dfrac{A\sin 180}{A+B\cos 180}=0 \\
& \Rightarrow \phi =0{}^\circ \\
\end{align}$
I.e. The resultant force makes an angle $0{}^\circ $ with the Bigger force A. So the resultant force is in the same direction as of A.
So the resultant will have magnitude $A-B$ and will be in the same direction as of A.
So, the correct answer is “Option B”.
Note: The quantity which has both magnitude and direction is called a vector quantity. But even if current has both magnitude and direction, it is a scalar quantity. In vector addition and subtraction the vector laws should be followed. And for direction of the resultant vector the triangle law and parallelogram law should be used.
Formula used: If the angle between the resultant force and force A is $\phi$ and the angle between the forces A and B is $\theta$ then the resultant of A and B has magnitude
$\left| \overrightarrow{A}+\overrightarrow{B} \right|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }$
$\tan \phi =\dfrac{A\sin \theta }{A+B\cos \theta }$
Complete step by step answer:
The magnitude of A and B is given by
$\begin{align}
& \left| \overrightarrow{A}+\overrightarrow{B} \right|=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta } \\
& =\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos 180} \\
& =\sqrt{{{A}^{2}}+{{B}^{2}}-2AB} \\
& =\sqrt{{{\left( A-B \right)}^{2}}} \\
& =A-B \\
\end{align}$
Consider the angle between the resultant force and the bigger force A is $\phi$. As A and B are in opposite directions then the angle between A and B is $\theta =180{}^\circ $ .
Then
$\begin{align}
& \tan \phi =\dfrac{A\sin \theta }{A+B\cos \theta }=\dfrac{A\sin 180}{A+B\cos 180}=0 \\
& \Rightarrow \phi =0{}^\circ \\
\end{align}$
I.e. The resultant force makes an angle $0{}^\circ $ with the Bigger force A. So the resultant force is in the same direction as of A.
So the resultant will have magnitude $A-B$ and will be in the same direction as of A.
So, the correct answer is “Option B”.
Note: The quantity which has both magnitude and direction is called a vector quantity. But even if current has both magnitude and direction, it is a scalar quantity. In vector addition and subtraction the vector laws should be followed. And for direction of the resultant vector the triangle law and parallelogram law should be used.
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