Two aqueous solutions are mixed in a chemical reaction. The substances in this beaker represent the products of this chemical reaction. Which substance(s) in the particulate-level diagram is a spectator ion?
(A) A and D
(B) B and C
(C) D
(D) B
Answer
615.9k+ views
Hint: Spectator ions can be either cations (positively-charged ions) or anions (negatively-charged ions). On both sides of a chemical equation, the ion is unchanged and does not affect equilibrium. Spectator ions detected in the original equation are ignored when writing a net ionic equation. The total ionic reaction, therefore, is distinct from the net chemical reaction.
Complete Step-by-Step solution :
By looking at the figure provided to us, we can see that there are four types of substance present in the beaker. They are A, B, C, and D. Also, we can observe that substances A and D are in the middle of the beaker or we can say they are very well mixed up in the liquid while substances B and C are settled at the bottom of the beaker.
We can observe that the substance A and D are a part of the chemical reaction. We can say this because both these substances A and D are found to be in the middle of the beaker. That is, they are taking part in the chemical reaction and they are not separate from the chemical process.
While looking at substances B and C, we can see that both these substances are settled at the bottom of the beaker during the mixture of the two aqueous solutions. We can say that substances B and C are acting as precipitate and it is also taking part in the chemical reaction.
Now, if we go through the basic definition of the spectator ion, we know that spectator ions have to be in the same phase of the reaction mixture. That is, as per our question, they have to be in a liquid phase.
So, we can conclude that substance A and substance D are in the same phase as the reaction mixtures, that is, the liquid phase. Hence, they are the spectator ions.
While substance B and C are precipitates in the beaker and they are not in the same phase of the reaction mixture.
Hence, the correct option is (A).
Note:
The chemical species that undergo a chemical change are indicated by the net ionic equation. On both sides of the equation, the ions that appear remain constant and are therefore considered spectator ions.
Complete Step-by-Step solution :
By looking at the figure provided to us, we can see that there are four types of substance present in the beaker. They are A, B, C, and D. Also, we can observe that substances A and D are in the middle of the beaker or we can say they are very well mixed up in the liquid while substances B and C are settled at the bottom of the beaker.
We can observe that the substance A and D are a part of the chemical reaction. We can say this because both these substances A and D are found to be in the middle of the beaker. That is, they are taking part in the chemical reaction and they are not separate from the chemical process.
While looking at substances B and C, we can see that both these substances are settled at the bottom of the beaker during the mixture of the two aqueous solutions. We can say that substances B and C are acting as precipitate and it is also taking part in the chemical reaction.
Now, if we go through the basic definition of the spectator ion, we know that spectator ions have to be in the same phase of the reaction mixture. That is, as per our question, they have to be in a liquid phase.
So, we can conclude that substance A and substance D are in the same phase as the reaction mixtures, that is, the liquid phase. Hence, they are the spectator ions.
While substance B and C are precipitates in the beaker and they are not in the same phase of the reaction mixture.
Hence, the correct option is (A).
Note:
The chemical species that undergo a chemical change are indicated by the net ionic equation. On both sides of the equation, the ions that appear remain constant and are therefore considered spectator ions.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

