Question

Two adjacent sides of a rectangle are 3a-b and 6b-a, then what is its perimeter?

Answer 1

Hint: Questions based on the parameter of a rectangle can be answered by use of a basic formula of the perimeter of a rectangle. Here is this particular question both length and width is given. So we just need to replace length and width with sides given in the question i.e. 3a-b and 6b-a. We will get the required answer.

Complete step-by-step answer:
Let the length of the rectangle be 3a-b and the width be 6b-a.
We know that formula of perimeter of a rectangle = 2(length + width)
So by replacing the values of length and width in the formula we get,
Perimeter of rectangle = 2[(3a-b) + (6b-a)]
on simplifying this, we get.
= 2[3a-b+6b-a]
We just need to do simple addition and subtraction, we have
=2[2a+5b]
Multiplying 2 on both the terms,
=4a+10b


So the perimeter of the rectangle = 4a+10b

Note: A quadrilateral's perimeter is defined as the sum of every side of the quadrilateral. In the case of a rectangle, the opposing sides of a rectangle are identical, such that the perimeter is double the width of the rectangle and twice the height of the rectangle and it is denoted by the letter ‘ P ‘.
and the area of the rectangle is Area=length$\times$width.