How many total atoms are there in $0.660\,g$ of ${P_2}{O_5}$ ?
Answer
607.2k+ views
Hint: The total mass occupied by Avogadro’s number of particles I.e.,$6.022 \times {10^{23}}$ particles of a substance is known as its molar mass. It is generally provided in the units of$gram\left( {gm} \right)$ and is numerically equal to the molar mass of the molecule. We can easily figure this out that a mole of ${P_2}{O_5}$ has a total of seven mole of atoms – two moles of phosphorus atoms and five moles of oxygen atoms.
In the given question, we have to find the total number of atoms in $0.660\,g$ of ${P_2}{O_5}$. We will do so by calculating moles of ${P_2}{O_5}$ then by using mole concept and unitary method, we will solve this problem.
Complete step-by-step answer:We will first calculate the molar mass of ${P_2}{O_5}$ $ = 2 \times 31 + 5 \times 16 = 62 + 80 = 142g\,mo{l^{ - 1}}$
We know that,
$142\,g\,mo{l^{ - 1}}$ or one mole of ${P_2}{O_5}$ contains $7$moles of atoms i.e., $7 \times {N_A}$ number of atoms $ = 7 \times 6.022 \times {10^{23}}$atoms
By using unitary method, we can write
$1g$ of ${P_2}{O_5}$ will contain $\dfrac{{7 \times 6.022 \times {{10}^{23}}}}{{142}}$ atoms
$0.660\,g$ of ${P_2}{O_5}$ will contain $\dfrac{{7 \times 6.022 \times {{10}^{23}}}}{{142}}$$ \times 0.660$ atoms $ = 1.95 \times {10^{22}}$atoms
Hence, $ = 1.95 \times {10^{22}}$ is the correct answer.
Additional information:Molar mass is the mass of $6.022 \times {10^{23}}$atoms (or one mole atoms) of an element expressed in grams.
Note: Here precaution must be taken while handling the numerical calculations as a small error in calculation could make a drastic change thus, we must try to do calculations that are precise to the very decimal points. Also, we must take note about the units of weight and molar mass in the question as this sometimes leads to grave calculative errors especially when weight is given in units other than the standard S.I. units of$grams\left( {gm} \right)$, commonly the weight is provided in units of microgram, milligram, nanogram etc. other than the standard units of gram. Another common mistake done by students is not reading what is asked in the question properly; sometimes we are tasked with finding the number of oxygen atoms in moles and not in grams. In those cases we should only provide answers to what is asked and not to what all we can.
In the given question, we have to find the total number of atoms in $0.660\,g$ of ${P_2}{O_5}$. We will do so by calculating moles of ${P_2}{O_5}$ then by using mole concept and unitary method, we will solve this problem.
Complete step-by-step answer:We will first calculate the molar mass of ${P_2}{O_5}$ $ = 2 \times 31 + 5 \times 16 = 62 + 80 = 142g\,mo{l^{ - 1}}$
We know that,
$142\,g\,mo{l^{ - 1}}$ or one mole of ${P_2}{O_5}$ contains $7$moles of atoms i.e., $7 \times {N_A}$ number of atoms $ = 7 \times 6.022 \times {10^{23}}$atoms
By using unitary method, we can write
$1g$ of ${P_2}{O_5}$ will contain $\dfrac{{7 \times 6.022 \times {{10}^{23}}}}{{142}}$ atoms
$0.660\,g$ of ${P_2}{O_5}$ will contain $\dfrac{{7 \times 6.022 \times {{10}^{23}}}}{{142}}$$ \times 0.660$ atoms $ = 1.95 \times {10^{22}}$atoms
Hence, $ = 1.95 \times {10^{22}}$ is the correct answer.
Additional information:Molar mass is the mass of $6.022 \times {10^{23}}$atoms (or one mole atoms) of an element expressed in grams.
Note: Here precaution must be taken while handling the numerical calculations as a small error in calculation could make a drastic change thus, we must try to do calculations that are precise to the very decimal points. Also, we must take note about the units of weight and molar mass in the question as this sometimes leads to grave calculative errors especially when weight is given in units other than the standard S.I. units of$grams\left( {gm} \right)$, commonly the weight is provided in units of microgram, milligram, nanogram etc. other than the standard units of gram. Another common mistake done by students is not reading what is asked in the question properly; sometimes we are tasked with finding the number of oxygen atoms in moles and not in grams. In those cases we should only provide answers to what is asked and not to what all we can.
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