
Toss a coin for a number of times as shown in the table. And record your findings in the table.
Number of Tosses Number of heads Number of tails \[10\] $20$ $30$ $40$ $50$
What happens if you increase the number of tosses more and more.
| Number of Tosses | Number of heads | Number of tails |
| \[10\] | ||
| $20$ | ||
| $30$ | ||
| $40$ | ||
| $50$ |
Answer
460.2k+ views
Hint: We need to manually toss a coin for the given number of times. Each time we record the occurrence and then count the number of heads and tails we get. Then we need to check how the probability of occurrence of heads is related to the probability of occurrence of tails. The probability of an event is defined as the possibility of the event occurring. The formula of probability is the ratio of the number of favorable outcomes and the total number of outcomes.
Complete answer:
First, we toss a coin $10$ times and observe that the head appears $6$ times and the tail appears $4$ times.
Again, we tossed the coin for $20$ times and observed that the head appears $12$ times and the tail appears $8$ times.
When we toss it for $30$ times we get $12$ heads and $18$ tails.
Next, when we toss the coin for $40$ times we record that the head appears for $18$ times and the tail appears for $22$ times.
Lastly, when we toss the coin for $50$ times we get $27$ heads and $23$ tails.
The table now looks like this:
The probability of getting head in $10$ tosses is $\dfrac{6}{{10}} = 0.6$.
The probability of getting tail in $10$ tosses is $\dfrac{4}{{10}} = 0.4$.
The probability of getting head in $20$ tosses is $\dfrac{{12}}{{20}} = 0.6$.
The probability of getting tail in $20$ tosses is $\dfrac{8}{{20}} = 0.4$.
The probability of getting head in $30$ tosses is $\dfrac{{12}}{{30}} = 0.4$.
The probability of getting tail in $30$ tosses is $\dfrac{{18}}{{30}} = 0.6$.
The probability of getting head in $40$ tosses is $\dfrac{{18}}{{40}} = 0.45$.
The probability of getting tail in $40$ tosses is $\dfrac{{22}}{{40}} = 0.55$.
The probability of getting head in $50$ tosses is $\dfrac{{27}}{{50}} = 0.54$.
The probability of getting tail in $50$ tosses is $\dfrac{{23}}{{50}} = 0.46$.
As we increase the number of tosses the chances of getting the number of heads and tails to become equal.
Note:
The probability of a head and a tail is the same. For a small number of tosses, we cannot predict if heads will occur more or tails. It can be both ways. But when we have a large number of tosses we mostly have an equal number of heads and tails. We can continue this experiment even for a larger number of tosses and record the results.
Complete answer:
First, we toss a coin $10$ times and observe that the head appears $6$ times and the tail appears $4$ times.
Again, we tossed the coin for $20$ times and observed that the head appears $12$ times and the tail appears $8$ times.
When we toss it for $30$ times we get $12$ heads and $18$ tails.
Next, when we toss the coin for $40$ times we record that the head appears for $18$ times and the tail appears for $22$ times.
Lastly, when we toss the coin for $50$ times we get $27$ heads and $23$ tails.
The table now looks like this:
| Number of Tosses | Number of heads | Number of tails |
| \[10\] | $6$ | $4$ |
| $20$ | $12$ | $8$ |
| $30$ | $12$ | $18$ |
| $40$ | $18$ | $22$ |
| $50$ | $27$ | $23$ |
The probability of getting head in $10$ tosses is $\dfrac{6}{{10}} = 0.6$.
The probability of getting tail in $10$ tosses is $\dfrac{4}{{10}} = 0.4$.
The probability of getting head in $20$ tosses is $\dfrac{{12}}{{20}} = 0.6$.
The probability of getting tail in $20$ tosses is $\dfrac{8}{{20}} = 0.4$.
The probability of getting head in $30$ tosses is $\dfrac{{12}}{{30}} = 0.4$.
The probability of getting tail in $30$ tosses is $\dfrac{{18}}{{30}} = 0.6$.
The probability of getting head in $40$ tosses is $\dfrac{{18}}{{40}} = 0.45$.
The probability of getting tail in $40$ tosses is $\dfrac{{22}}{{40}} = 0.55$.
The probability of getting head in $50$ tosses is $\dfrac{{27}}{{50}} = 0.54$.
The probability of getting tail in $50$ tosses is $\dfrac{{23}}{{50}} = 0.46$.
As we increase the number of tosses the chances of getting the number of heads and tails to become equal.
Note:
The probability of a head and a tail is the same. For a small number of tosses, we cannot predict if heads will occur more or tails. It can be both ways. But when we have a large number of tosses we mostly have an equal number of heads and tails. We can continue this experiment even for a larger number of tosses and record the results.
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