Question

To which group, an element with atomic number 88 will belong?
A. Group 12
B. Group 17
C. Group 10
D. Group 2

Answer 1

Hint: In the periodic table group is a column containing a number of chemical elements. There are 18 groups in the periodic table. The elements in the same group have the same chemical properties because of the same number of valence electrons.

Complete step by step answer:
- The electronic configuration of the element with atomic number 88 is $[Element]7{{s}^{2}}$ .
- From the electronic configuration we can say that the valence electrons are present in s-orbital.
- Means the given element belongs to s-block.
- In s-block there are two groups Group-1 and Group-2.
- The electronic configuration of elements in group-1 is $n{{s}^{1}}$ .
- The electronic configuration of elements in group-2 is $n{{s}^{2}}$.
- Means the given element belongs to group-2 because of having two valence electrons in s-orbital.
- The elements present in the group-2 of periodic table are Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), Barium (Ba), and Radium (Ra).
- The atomic numbers of the elements in group-2 are Beryllium (4), Magnesium (12), Calcium (20), Strontium (38), Barium (56), and Radium (88).
Therefore the element which belongs to group-2 with atomic number 88 is radium.

Note: If we are supposed to find any element in the periodic table we should know the atomic number of that particular element. After knowing the atomic number we are supposed to write the electronic configuration of the element. By the electronic configuration we can easily find the position of the element in the periodic table.