Question

To what volume, in mL, must 50mL of 3.50M \[{H_2}S{O_4}\] be diluted in order to make \[2M\]\[{H_2}S{O_4}\]?
A. \[25\]
B. \[60.1\]
C. \[87.5\]
D. \[93.2\]
E. \[101\]

Answer 1

Hint: Molarity is defined as the measure of the concentration. It is expressed as the number of moles of solute per litre of the solution.

Complete step by step answer:
The answer to the question lies in the concept of dilution. A dilution of a solution occurs when a solution of a certain concentration is added more solvent in which the substance under consideration is likely to dissolve.
This results in the decrease of concentration with respect to the original solution. By adding more solvent to the solution the total volume of the solution increases as the concentration of the solution decreases.
The concentration and the volume of the concentrated or dilute solution can be determined using the equation of dilution
\[{M_1}{V_1}{\text{ }} = {\text{ }}{M_2}{V_2}\] ,
where \[{M_1}\] is the concentration of the concentrated solution in molarity units,
\[{V_2}\] is the volume of the concentrated solution in mL,
\[{M_2}\] is the concentration in molarity of the dilute solution,
\[{V_2}\] is the volume of the dilute solution in mL.
Given\[{M_1} = 3.50M\], \[{V_1} = {\text{ }}50mL\]
\[{M_2} = 2M\] , \[{V_2} = ?\]
Inserting in the equation,
${V_2} = \dfrac{{{M_1}{V_1}}}{{{M_2}}}$
${V_2} = \dfrac{{3.5 \times 50}}{2}$
${V_2} = 87.5mL$
Hence, option C is the correct answer, i.e. the volume of \[87.5mL\] is to be prepared for making \[2M\] \[{H_2}S{O_4}\].

Note:
The boiling point of haloalkanes decreases with branching. The haloalkanes are only very slightly soluble in water, but dissolves readily in organic solvents.