Question

To pass an examination, a candidate needs \[40\%\] marks. All questions carry equal marks. A candidate just passed by getting $10$ answers correct by attempting $15$ of the total questions. How many questions are there in the examination?
$\left( A \right)\text{ 25}$
$\left( B \right)\text{ 30}$
$\left( C \right)\text{ 40}$
$\left( D \right)\text{ 45}$

Answer 1

Hint: In order to find a solution to this problem, we will have to first convert this word problem into mathematical format and then after converting into mathematical form, we will have to create an equation or expression. After we have all the things we require, we will have to complete the calculation of our equation and then we will get our required answer.

Complete step by step answer:
As we know, we have our problem as a word problem, so we will first convert it into a mathematical problem.
Therefore, breaking down our problem into parts, we get:
Let the number of questions in the exam be $x$.
Let required number to pass the exam be $=\dfrac{40}{100}\times x$
Candidate just passed by getting \[10\] answers correct by attempting \[15\] total questions.
Therefore, we can write it as:
$10=\dfrac{40}{100}\times x$
Now, as we have gathered information, we will now create an expression based on the problem.
Therefore, expression can be written as,
$x=\dfrac{10\times 100}{40}$
Now, on solving our expression, we get:
$x=25$
Therefore, there are $25$ questions in the examination.

So, the correct answer is “Option A”.

Note: A word problem is a few sentences describing a 'real-life' scenario, where a problem needs to be solved in a way of a mathematical calculation.
To solve word problems, we have to read it well. One reason we struggle is because they have trouble with reading in general and not understanding the problem. To turn a word problem into a number sentence, we need to understand the language and concepts of math first and have some basic logic of algebraic concepts, then we can easily solve any word problem.