Courses
Courses for Kids
Free study material
Offline Centres
More

Three tables are purchased for Rs.\[2500\] each. First is sold at a profit of \[8\% \], the second is sold at a loss of \[3\% \]. If their average selling price is Rs.\[2575\], find the profit percent on the third.

seo-qna
Last updated date: 01st Mar 2024
Total views: 305.4k
Views today: 3.05k
IVSAT 2024
Answer
VerifiedVerified
305.4k+ views
Hint: The given problem is based on profit and loss concept; in this problem we can find profit percentage using the formula \[\left( {\dfrac{{profit}}{{cp}}} \right) \times 100\]and to find the selling price of first two tables we can make use of the formula \[sp = \left( {\dfrac{{100 + profit\% }}{{100}}} \right) \times cp\] and \[sp = \left( {\dfrac{{100 - loss\% }}{{100}}} \right) \times cp\] as per the requirement of the problem.

Complete step by step solution:
Given The cost of \[1\] table = Rs.\[2500\].
Then, the Cost price of the three tables = Rs. \[2500 \times 3 = 7500\]
Given The average Selling price of the \[3\] tables = Rs. \[2575\].
 Then, the total Selling price = Rs. \[2575 \times 3 = 7725\]
Now we have to calculate selling price of the first table using the formula \[sp = \left( {\dfrac{{100 + profit\% }}{{100}}} \right) \times cp\]
\[ \Rightarrow \] given The Selling price of the first table at \[8\% \] profit by using above formula
we get =\[\left( {\dfrac{{100 + 8}}{{100}}} \right) \times 2500\]
\[\therefore \] The Selling price of the first table=2700 Rs
Now we have to calculate selling price of the first table using the formula \[sp = \left( {\dfrac{{100 - loss\% }}{{100}}} \right) \times cp\]
\[ \Rightarrow \] given The Selling price of the second table at \[3\% \] loss by using above formula
we get =\[\left( {\dfrac{{100 - 3}}{{100}}} \right) \times 2500\]
\[\therefore \] The Selling price of the second table=2425 Rs
Then, the sum of the Selling price of two tables = \[(2700 + 2425) = 5125\]
So, the Selling price of the third table = The total of the Selling price − the sum of the Selling price of two tables
\[ = (7725 - 5125) = 2600\]Rs
Profit on the third tables \[ = (2600 - 2500) = 100\]Rs
$ = \dfrac{{100}}{{2500}} \times 100\% $
$
   = \dfrac{{100}}{{2500}} \times 100\% \\
   = 4\% \\
$
$ = 4\% $
 Therefore, profit percent on third table is \[4\% \]
So, the correct answer is “ \[4\% \]”.

Note: To solve the above problem we have used the direct formula along with unitary method (if the value of one unit is given then multiply the value of a single unit to the number of units to get necessary value) where ever necessary because as in the problem cost of each table is given.
Trending doubts