Question

There is a S-S linkage in:
A.\[{{S}_{2}}{{O}_{3}}^{2-}\]
B.\[{{S}_{2}}{{O}_{4}}^{2-}\]
C.\[{{S}_{2}}{{O}_{5}}^{2-}\]
D.\[{{S}_{2}}{{O}_{7}}^{2-}\]

Answer 1

Hint: We know the rule for a molecule to contain S – S linkage in it. So, find out the oxidation state of sulphur in each of the molecules given in the question and find out which molecules have S- S linkage.

Complete step by step answer:
If the oxidation state of sulphate is less than 6, then direct linkage is present. By direct linkage we mean the S – S linkage nothing but the sulphate to sulphate linkage.
If the oxidation state of sulphate is equal to 6, then we can see the existence of S – O – S linkage. It is nothing but the linkage of Sulphate to oxygen and oxygen to sulphate. ( Two sulphates and one oxygen )
If the oxidation state of sulphate is greater than 6, then peroxy linkage is present. By per-oxy linkage we mean sulphate to oxygen, oxygen to oxygen and oxygen to sulphate.( Two sulphates and two oxygens ) ( S – O – O – S linkage is present)
So for getting the S – S linkage we must have the oxidation state of sulphate presents in the molecule to be less than 6.
Let us find out the oxidation state of Sulphur in option 1
\[\Rightarrow 2x+3(-2)=-2\]
\[\Rightarrow x=2\]
So, the oxidation state of Sulphur in \[{{S}_{2}}{{O}_{3}}^{2-}\] is 2. So, it has a S – S bond in it.
Let us find out the oxidation state of Sulphur in option 2
\[\Rightarrow 2x+4(-2)=-2\]
\[\Rightarrow x=3\]
So, the oxidation state of Sulphur in \[{{S}_{2}}{{O}_{4}}^{2-}\] is 3. So, it has S – S bond in it.
Let us find out the oxidation state of Sulphur in option 3
\[\Rightarrow 2x+5(-2)=-2\]
\[\Rightarrow x=4\]
So, the oxidation state of Sulphur in \[{{S}_{2}}{{O}_{5}}^{2-}\] is 4. So, it has a S – S bond in it.
Let us find out the oxidation state of Sulphur in option 4
\[\Rightarrow 2x+7(-2)=-2\]
\[\Rightarrow x=6\]
So, the oxidation state of Sulphur in \[{{S}_{2}}{{O}_{7}}^{2-}\] is 6. So, it does not have a S – S bond in it.

So, Option A, B and C are correct.

Note: We already know the oxidation state of oxygen is always –2, that is why we multiply the number of oxygen atoms to –2. There may be a possibility for getting more than one answer in any question. So, we have to check each and every option.