Question

There are two candidates in an election 11% of the voters did not vote. 500 votes were declared invalid. The elected candidate 3300 votes more than his opponents. If the elected candidate got 48% of the total votes, how many votes did each candidate get?

Answer 1

Hint: As we know, 2 candidates are there and if we assume the total votes is 100% then out of this 100%, 11% are non-voters, Also, 500 voters declared invalid. And the candidates who got elected have 3300 more votes than opponents. And here also mentioned that only 48% of total votes gain by elected candidates.

Complete step by step solution:
Let voters are 100%, then,

100% (voters)

               

                                  11% (did not vote) 89% (given vote)
                              

                                                               500 (votes are invalid) 89% - 500 (votes are valid)

Elected candidate got 48% of total vote then loser candidate got (89% - 500 – 48%)
                              89% - 500 (votes are valid)
           

48% (winner candidate) (89% - 500 – 48%) loser candidate

Elected candidate got 3300 votes more than his opponent.
$\therefore$ winner candidate – loser candidate = 3300
 48% -( 89%-500-48%) = 3300
 48% -( 41%-500)= 3300
 48% - 41%+500 =3300
 7% = 2800
 1% = 400
 100% = 40000
Total voters (votes) = 40000
Winner candidate = 40000 $\times {\displaystyle \frac{48}{100}}$ = 19200 votes.
Loser candidate = 19200 – 3300 = 15900 votes.

Therefore, the required value is (19200) & (15900) votes.



Note: first to take votes (total) is 100% then process the question winner candidate is 48% of total votes and loser candidate gets 3300 votes less than winner candidate.