Question

There are Four Points $A,B,C,D$ on a straight line the distance between $A$ and $B$ is $3cm$. $C$ and $D$ are both twice as far from $A$ as from $B$ then the distance between $C$ and $D$ is
$A)1cm$
$B)2cm$
$C)3cm$
$D)4cm$

Answer 1

Hint: To solve this question we need to have the knowledge of Arithmetic operation. To solve this question we will follow each condition step by step. We will draw a line and mark the point so that calculation becomes easier.

Complete step by step answer:
The question ask us to find the value of find the distance between $C$ and $D$ when there are four points $A,B,C,D$ on a straight line and the distance between $A$ and $B$ is $3cm$. The first step to solve the problem is to draw a straight horizontal line and label the points.
To solve the question we will start with analysing each condition. The first step will be to mark point $A$ and $B$with having $3cm$.

The second condition states that $C$ and $D$ are both twice as far from $A$ as from $B$. On the basis of the above condition/ fact point $CD$ is twice as the length of $AB$. Keeping in mind the above analysis we will draw these points on the number line. Length of $BC$ is not mentioned in the question, so when drawn the length should be any thing.

On arranging the points on the straight line we infer that the length $CD$ is:
_{$\Rightarrow CD=2AB$
The length of $AB$ is given as $3cm$, so on substituting the value we get:}
\[\Rightarrow CD=2\left( 3cm \right)\]
$\Rightarrow CD=6cm$
$\therefore $ The distance between $C$ and $D$ is $C)6cm$.

Note: To solve these kinds of questions, always keep in mind that these questions are solved in the same series as per the conditions given in the question. If we skip any of the conditions we will be unable to solve the problem.