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The weight of Rahul is 5 kg more than Sachin, the weight of Samir is 12 kg less than double the weight of Sachin. If the total weight of all the three is 93, find the weight of each of them.
A. Sachin - 25 kg, Rahul - 30 kg, Samir - 38 kg
B. Sachin - 25 kg, Rahul - 30 kg, Samir - 40 kg
C. Sachin - 25 kg, Rahul - 38 kg, Samir - 25 kg
D. Sachin - 25 kg, Rahul - 38 kg, Samir - 38 kg

Answer
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Hint: In order to solve this question, we will consider the weight of Sachin, Rahul and Samir as x kg, y kg and z kg respectively. Then we will try to form a linear equation from the given conditions and then by substitution method, we will try to get the value of x, y and z and hence get the answer.

Complete step-by-step answer:
In this question, we have been asked to find the weight of Sachin, Rahul and Samir for a few given conditions. To solve this question, we will first consider the weight of Sachin as x kg, Rahul as y kg and Samir as z kg. Now we have been given that the weight of Rahul is 5 kg more than the weight of Sachin. So, we can say that,
y = x + 5 ………… (i)
We have also been given that the weight of Samir is 12 kg less than double the weight of Sachin. So, we can say that,
z = 2x - 12 ………… (ii)
We also have been given that the total weight of the three of them is 93 kg. So, we can write it as,
x + y + z = 93 ………… (iii)
Now, we will put the value of y and z from equations (i) and (ii) in equation (iii). So, we get,
x + (x + 5) + (2x - 12) = 93
Now, we will simplify it to get the value of x. So, we get,
4x - 7 = 93
4x = 93 + 7
4x = 100
And, x = 25
Now, we will put the value of x in equation (i) and (ii) to get the values of y and z. So, we get,
y = 25 + 5 and z = 2(25) - 12
So, y = 30 and z = 38
Hence, we get the values of x, y, and z as 25, 30, and 38. Therefore the weight of Sachin is 25 kg, Rahul is 30 kg and Samir is 38 kg.
Hence, option A is the correct answer.

Note: We can also solve this question by using the options one by one and checking which option satisfies all the given conditions. It could be a shortcut method for the students who are really fast with calculations, but there are chances of calculation mistakes too. So, it is better to solve this question by the conventional method.