Question

The weight of a molecule of the compound\[{{C}_{6}}{{H}_{12}}{{O}_{6}}\] is about
A) \[180g\]
B) \[3\times {{10}^{-22}}g\]
C) \[22\times {{10}^{-23}}g\]
D) \[132g\]

Answer 1

Hint: We can calculate molecular weight of the compound in chemistry by multiplying the atomic weight in the atomic mass unit of each of the element present in the chemical formula by the amount of the atoms of that element which are present in formula then put all the products together. This \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]is the chemical formula of glucose. Glucose is an essential constituent which we need and take it from our food by a balanced diet.

Complete step-by-step answer:
The unit which we use to express the molar mass of the compound is gram per mole (g/mol). While we start to calculate the molecular weight of the compound we get to know the number of grams in one mole of that substance. The formula weight is considered as the essential weight which we calculate in the atomic mass unit of the atoms present in the formula.

The chemical compound given to us is \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]which contains six carbon atom, twelve hydrogen atoms and six carbon atoms. So the atomic weight of carbon, hydrogen and oxygen is 12, 1 and 16 respectively, so now we will calculate the mass for 1 mole of compound.
Weight of compound = \[12\times 6+12\times 1+16\times 6\]
Weight of compound= \[72+12+96\]
Weight of compound= $180g/mol$
1 mole of compound= $180g$
Weight of 1 molecule is =\[6.022\times {{10}^{+23}}\] g
So the weight of 1 molecule of \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]=\[\dfrac{180}{6.022\times {{10}^{+23}}}\]= \[30\times {{10}^{-23}}=3\times {{10}^{-22}}g\]

Hence the correct answer is option ‘B’.

Note: Glucose when heated with hydrogen iodide forms n- hexane chain which indicates that all the six carbons are attached in a straight chain to each other. The glucose gets oxidised to carboxylic acid when glucose is reacted with the mild oxidising agent such as bromine water. in helps in treating the high level of potassium in the blood