Question

The weight of $63$ articles is $7kg$
A. What is the weight of $90$ such articles?
B. How many such articles would weigh $5kg$?

Answer 1

Hint: We will make use of the unitary method to solve the given problem. Which is to convert the given quantities into one term and then solve according to them like from the given we have two quantities, kilogram and weight of the articles. Hence, we will convert them as weight to solve the first question and then we will convert them as kilograms to solve the second question.

Complete step by step answer:
Since from the given we have weight of $63$ articles are $7kg$
To find a) What is the weight of $90$ such articles?
Since we known that weight of $63$ articles is $7kg$ and which can be expressed mathematically as weight of $63A = 7kg$
Hence, we will divide them with the number sixty-three then we have weight of $1A = \dfrac{7}{{63}}kg$
Then by division operation and from given is the weight of $90$ such articles, hence we have $90 \times 1A = 90 \times \dfrac{7}{{63}}kg \Rightarrow 90A = 10kg$
Hence $10kg$ is the weight of $90$ such articles
To find b) How many such articles would weigh $5kg$?
Since we know that the weight of $63$ articles is $7kg$ and which can be expressed mathematically as weight of $7kg = 63A$ weight.
Hence, we have $1kg = \dfrac{{63}}{7}A$
Also, many such articles would weight $5kg$ then we get $5kg = 5 \times \dfrac{{63}}{7}A \Rightarrow 5kg = 45A$
Hence $45$ articles would weight $5kg$

Note:
The operations which we used to solve the problem are multiplication and division operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$ is called the multiplicand and the number $7$is called the multiplier.
The process of the inverse of the multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $90 \times 1A = 90 \times \dfrac{7}{{63}}kg \Rightarrow 90A = 10kg$