Question

The volume of gases evolved when dil $ {{H}_{2}}S{{o}_{4}} $ electrolyzed using $ 2F $ at $ STP $ is
(A) $ 22.4L $
(B) $ 11.2L $
(C) $ 33.6L $
(D) $ 44.8L $

Answer 1

Hint: Electrolysis :- The process of a that causing chemical reaction by passing an current through a liquid solution of substance. As a result it breaks down into its respective anion and cation.

Complete Step By Step Solution
Electrolysis of dil $ {{H}_{2}}S{{o}_{4}} $ :- Dilate sulphuric acid consists of water molecules. The ion present in dil $ {{H}_{2}}S{{o}_{4}} $ are $ {{H}_{2}}^{{{+}_{{}}}}OH $ ion from water and $ {{H}^{+}} $ and ion from the sulphuric acid . The positive ions attracted towards the cathode whereas negative ions towards the anode.
Reaction takes place cathode
 $ 2{{H}^{+}}+2{{e}^{-}}\to {{H}_{2}} $
At Anode
 $ 4o{{H}^{-}}\to {{o}_{2}}+2{{H}_{2}}o+4{{e}^{-}} $
2 moles of electrons gives us one mole of $ {{o}_{2}}2{{H}_{2}} $ when $ 2F $ electricity gives 2 moles of gases .
Mole of gases at $ STP $ is equivalent to = $ 22.4L $
Mole of gases at $ STP $ is equivalent to = $ 2\times {{22}_{4}} $
= $ 44.8L $
So, the ‘D’ is the correct option

Note
The knowledge of the electrolysis of dil sulphuric acid must be the knowledge of how much litre of gas consists of $ STP $ of 1 mole because all these things helpful to solve the problem.Related to electrolysis of liquid.