Answer
Verified
394.5k+ views
Hint: The compressibility factor gives us an idea about the degree to which a real gas shows deviation from the ideal gas behaviour. It is the ratio of the observed molar volume of a gas to the calculated molar volume (using ideal gas equation) of the gas at the same pressure and temperature
Complete answer:
The compressibility factor for a gas is the ratio of the observed molar volume of a gas to the calculated molar volume (using ideal gas equation) of the gas at the same pressure and temperature. It can also be defined as the ratio of the product and pressure and volume of the gas to the product of the number of moles, the gas constant and the temperature of the gas. The equations are given below:
$ Z=\cfrac { PV }{ nRT } $ (Where Z is the compressibility factor)
$ \Rightarrow Z=\cfrac { P{ V }_{ real } }{ nRT } $...(1)
Since according to the ideal gas equation: $ PV=nRT$
$ \Rightarrow { V }_{ real }=\cfrac { nRT }{ P } $
Putting the above equation in equation (1),
$ Z=\cfrac { { V }_{ real } }{ { V }_{ ideal } } $
For an ideal gas, $ { V }_{ real }={ V }_{ ideal }$. Hence the compressibility factor for an ideal gas is equal to 1.
For a real gas compressibility factor can be less than 1 or greater than 1:
If the compressibility factor is less than 1 then, the gas will show negative deviation and it will be more compressible than expected. Example: methane gas, carbon dioxide gas.
If the compressibility factor is greater than 1 then the gas shows positive deviation and will be less compressible than expected. Example: Helium gas, Hydrogen gas.
So, the correct answer is “Option B”.
Note: If the compressibility factor is less than 1 then it implies that the attractive forces are predominant among the gas molecules. If the compressibility factor is more than 1 it implies that the repulsive forces are predominant among the gas molecules. Whether the compressibility factor will be greater than or less than 1 at a particular temperature and pressure will depend upon the nature of the gas.
Complete answer:
The compressibility factor for a gas is the ratio of the observed molar volume of a gas to the calculated molar volume (using ideal gas equation) of the gas at the same pressure and temperature. It can also be defined as the ratio of the product and pressure and volume of the gas to the product of the number of moles, the gas constant and the temperature of the gas. The equations are given below:
$ Z=\cfrac { PV }{ nRT } $ (Where Z is the compressibility factor)
$ \Rightarrow Z=\cfrac { P{ V }_{ real } }{ nRT } $...(1)
Since according to the ideal gas equation: $ PV=nRT$
$ \Rightarrow { V }_{ real }=\cfrac { nRT }{ P } $
Putting the above equation in equation (1),
$ Z=\cfrac { { V }_{ real } }{ { V }_{ ideal } } $
For an ideal gas, $ { V }_{ real }={ V }_{ ideal }$. Hence the compressibility factor for an ideal gas is equal to 1.
For a real gas compressibility factor can be less than 1 or greater than 1:
If the compressibility factor is less than 1 then, the gas will show negative deviation and it will be more compressible than expected. Example: methane gas, carbon dioxide gas.
If the compressibility factor is greater than 1 then the gas shows positive deviation and will be less compressible than expected. Example: Helium gas, Hydrogen gas.
So, the correct answer is “Option B”.
Note: If the compressibility factor is less than 1 then it implies that the attractive forces are predominant among the gas molecules. If the compressibility factor is more than 1 it implies that the repulsive forces are predominant among the gas molecules. Whether the compressibility factor will be greater than or less than 1 at a particular temperature and pressure will depend upon the nature of the gas.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE