
The value of \[\sin \left( {90 - \theta } \right) \cdot \cos \theta + \sin \theta \cdot \cos \left( {90 - \theta } \right)\] is equal to
A.0
B.1
C.2
D.None of these
Answer
594.6k+ views
Hint: First, we will use the value \[\sin \left( {90 - \theta } \right) = \cos \theta \] and \[\cos \left( {90 - \theta } \right) = \sin \theta \] in the given value and then the property of trigonometric functions,\[{\cos ^2}\theta + {\sin ^2}\theta = 1\] in the obtained equation to find the required value.
Complete step by step answer:
We are given that \[\sin \left( {90 - \theta } \right) \cdot \cos \theta + \sin \theta \cdot \cos \left( {90 - \theta } \right)\].
Using the value \[\sin \left( {90 - \theta } \right) = \cos \theta \] and \[\cos \left( {90 - \theta } \right) = \sin \theta \] in the given value, we get
\[
\Rightarrow \cos \theta \cdot \cos \theta + \sin \theta \cdot \sin \theta \\
\Rightarrow {\cos ^2}\theta + {\sin ^2}\theta \\
\]
Using the property of trigonometric functions,\[{\cos ^2}\theta + {\sin ^2}\theta = 1\] in the above equation, we get
\[ \Rightarrow 1\]
Hence, option B is correct.
Note: In these types of questions, the key concept to solve this is to learn about the complementary angles of trigonometric ratios. Students need to learn about the basic trigonometric identities to solve such problems.
Complete step by step answer:
We are given that \[\sin \left( {90 - \theta } \right) \cdot \cos \theta + \sin \theta \cdot \cos \left( {90 - \theta } \right)\].
Using the value \[\sin \left( {90 - \theta } \right) = \cos \theta \] and \[\cos \left( {90 - \theta } \right) = \sin \theta \] in the given value, we get
\[
\Rightarrow \cos \theta \cdot \cos \theta + \sin \theta \cdot \sin \theta \\
\Rightarrow {\cos ^2}\theta + {\sin ^2}\theta \\
\]
Using the property of trigonometric functions,\[{\cos ^2}\theta + {\sin ^2}\theta = 1\] in the above equation, we get
\[ \Rightarrow 1\]
Hence, option B is correct.
Note: In these types of questions, the key concept to solve this is to learn about the complementary angles of trigonometric ratios. Students need to learn about the basic trigonometric identities to solve such problems.
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