Question

The value of Henry’s constant ${{K}_{H}} $ is
(A) greater for gases with higher solubility
(B) greater for gases with lower solubility
(C) constant for all gases
(D) not related to the solubility of gases

Answer 1

Hint: To solve this question refer to the henry law, as we know that it tells us about the relation between temperature, amount of gas and partial pressure, and it was formulated by William henry.

Complete answer:
We have been asked about the value of henry’s constant that is ${{K}_{H}} $,
So, for that:
Firstly, we know about the henry law which tells us the relation between temperature, amount of gas and partial pressure,
So, according to henry’s law the amount of gas that dissolves in a liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid at constant temperature,
$P \propto C$
\[P={{K}_{H}}C\]
Where, P is the partial pressure of the gas, ${{K}_{H}} $ is the henry’s constant and C is the amount of the gas dissolved,
So, if we find the in terms of henry’s constant: ${{K}_{H}} \propto \dfrac{1}{C} $
So, for a highly soluble gas, the value of henry’s constant is very less and for gases with lower solubility value of henry’s constant is very high,
So, we can say that the value of ${{K}_{H}} $is greater for gases with lower solubility,

So, we can conclude that the correct option is (B).

Note:
Henry’s law has certain applications, like the amount of oxygen that dissolves in the bloodstream is directly proportional to the partial pressure of oxygen in the alveoli air is one of the applications, then also in the carbonated drinks the gas dissolved due to henry law.