Question

The value of \[\cot {15^\circ }\cot {20^\circ }\cot {70^\circ }\cot {75^\circ }\] is equal to
A) -1
B) 0
C) 1
D) 2

Answer 1

Hint: We know that an equation involving one or more trigonometric ratios of unknown angles is called a trigonometric equation. To evaluate the given trigonometric function, the equation consists of cot functions, as we know that \[\tan \left( {{{90}^\circ } - \theta } \right) = \cot \theta \]hence, by applying this we can evaluate the given functions.

Complete step-by-step solution:
The given function is
\[\cot {15^\circ }\cot {20^\circ }\cot {70^\circ }\cot {75^\circ }\]
As we know that \[\tan \left( {{{90}^\circ } - \theta } \right) = \cot \theta \], hence
= \[\cot {15^\circ }\cot {20^\circ }\tan \left( {{{90}^\circ } - {{70}^\circ }} \right)\tan \left( {{{90}^\circ } - {{75}^\circ }} \right)\]
Hence, simplifying the functions we get
\[\Rightarrow \cot {15^\circ }\cot {20^\circ }\tan {20^\circ }\tan {15^\circ }\]
Since, \[\cot \theta \tan \theta = 1\]
\[\Rightarrow \left( {\cot {{15}^\circ }\tan {{15}^\circ }} \right)\left( {\cot {{20}^\circ }\tan {{20}^\circ }} \right)\]
\[\Rightarrow 1 \times 1\]
$\Rightarrow 1$
Hence, we get the value of \[\cot {15^\circ }\cot {20^\circ }\cot {70^\circ }\cot {75^\circ }\]= 1

Therefore, option C is the correct answer.

Additional information: In trigonometry sin, cos and tan values are the primary functions we consider while solving trigonometric problems. These trigonometry values are used to measure the angles and sides of a right-angle triangle. Apart from sine, cosine and tangent values, other values are cotangent, secant and cosecant.
The trigonometric values are about the knowledge of standard angles for a given triangle as per the trigonometric ratios. Trigonometric ratios are Sine, Cosine, Tangent, Cotangent, Secant and Cosecant. All the trigonometrical concepts are based on these functions. Hence, to understand trigonometry further we need to learn these functions and their respective formulas at first.
If θ is the angle in a right-angled triangle, then
Sin θ = \[\dfrac{{perpendicular}}{{hypotenuse}}\]
Cos θ = \[\dfrac{{base}}{{hypotenuse}}\]
Tan θ = \[\dfrac{{perpendicular}}{{base}}\]

Note: The key point to evaluate any trigonometric function is that we must know all the basic trigonometric functions and their relation. As in the given equation consists of cot functions, hence we must know all the trigonometric identities with respect to the function, as we know that \[\tan \left( {{{90}^\circ } - \theta } \right) = \cot \theta \]hence, by applying this we can evaluate the given functions.