Question

The value of $100 - \left\{ {\left( {7\ of\ 8 + 4} \right) \div 5} \right\}$ is

Answer 1

Hint: We have to find the value of $100 - \left\{ {\left( {7\ of\ 8 + 4} \right) \div 5} \right\}$. It is simplified by the rule of “BODMAS”. While simplifying the bracket first of all solve the expression inside the ‘ \[\left( {} \right)\]’bracket then ‘ $\left\{ {} \right\}$’ bracket and finally ‘ $\left[ {} \right]$’. After performing the operation of brackets, perform the other operations in sequence according to the “BODMAS”. Then, we will get the required value.

Complete step by step solution:Here, the given expression is $100 - \left\{ {\left( {7 of 8 + 4} \right) \div 5} \right\}$.
First of all, solve the expression given inside the small bracket $\left( {} \right)$. Inside this small bracket there is an operator like “$of$” and “ $ + $” is present. So, firstly perform the operation on “ of” then addition. That is,
$= 100 - \left\{ {\left( {7\ of\ 8 + 4} \right) \div 5} \right\}$
$= 100 - \left\{ {\left( {56 + 4} \right) \div 5} \right\}$
$= 100 - \left\{ {60 \div 5} \right\} $
Now, simplify the expression inside the bracket ‘$\left\{ {} \right\}$’. Inside this only one operator, that is division, is present. So, simplifying this we get,
$ = 100 - \left\{ {60 \div 5} \right\}$
  $= 100 - 12 $
Finally, we perform the subtraction operation on the two numbers and we will get,
\[ = 100 - 12\]
\[ = 88\]

Thus, the value of $100 - \left\{ {\left( {7\ of\ 8 + 4} \right) \div 5} \right\}$ is $88$.

Note: Rule of “BODMAS”
If more than one operator is present in an expression then firstly solve the expression inside the brackets then the operator “ $of$”. After this perform division operation and then multiplication operation. Finally perform the addition and then subtraction operation.
The required arrangement of operators is Bracket $ > $ $of$$ > $Division $ > $Multiplication $ > $Addition $ > $Subtraction.
“ of” is an operator which is similar to multiplication but the only difference is that the “ of” operator is performed before the multiplication. Suppose we have to solve the value of $9\ of\ 6 \times 3$.
Firstly perform “ of” operation i.e $54 \times 3$ and then perform multiplication. Then we get the result $162$.