
The types of hybrid orbitals of nitrogen in , and respectively are expected to be:
A.
B.
C.
D.
Answer
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Hint: To find the types of hybrid orbitals involved in hybridization there is a formula. It is as follows.
Where H is the number of orbitals involved in hybridization
V is the number of valence electrons of central atom
M is the number of monovalent atoms attached to central atom
C = charge on the cation
A = charge on the anion
Complete step by step answer:
- The given molecules are , and .
- The structure of is as follows.
-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 0
C = charge on the cation = 1
A = charge on the anion = 0
- Therefore
- Number of hybrid orbital is equal to two means the hybridization is .
- The structure of is as follows.
-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 0
C = charge on the cation = 0
A = charge on the anion = 1
- Therefore
-Number of hybrid orbital is equal to three means the hybridization is .
-The structure of is as follows.
-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 4
C = charge on the cation = 1
A = charge on the anion = 0
- Therefore
-Number of hybrid orbital is equal to four means the hybridization is .
-The hybrid orbitals of nitrogen in , and are respectively.
So, the correct answer is “Option B”.
Note: If the number of orbitals involved in hybridization are 4 then the hybridization of the central atom is . If the number of orbitals involved in hybridization are 5 then the hybridization of the central atom is . If the number of orbitals involved in hybridization are 6 then the hybridization of the central atom is .
Where H is the number of orbitals involved in hybridization
V is the number of valence electrons of central atom
M is the number of monovalent atoms attached to central atom
C = charge on the cation
A = charge on the anion
Complete step by step answer:
- The given molecules are
- The structure of

-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 0
C = charge on the cation = 1
A = charge on the anion = 0
- Therefore
- Number of hybrid orbital is equal to two means the hybridization is
- The structure of

-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 0
C = charge on the cation = 0
A = charge on the anion = 1
- Therefore
-Number of hybrid orbital is equal to three means the hybridization is
-The structure of

-From the above structure we can say that
V= number of valence electrons of central atom = 5
M = number of monovalent atoms attached to central atom = 4
C = charge on the cation = 1
A = charge on the anion = 0
- Therefore
-Number of hybrid orbital is equal to four means the hybridization is
-The hybrid orbitals of nitrogen in
So, the correct answer is “Option B”.
Note: If the number of orbitals involved in hybridization are 4 then the hybridization of the central atom is
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