Question

The type of bonds present in \[CuS{O_4}.5{H_2}O\] are only:
(a) Electrovalent and covalent
(b) Electrovalent and coordinate covalent
(c) Electrovalent, covalent and coordinate covalent
(d) covalent and coordinate covalent

Answer 1

We know that elements and compounds form bonds among themselves to stabilize. Before solving this question it is understood that chemical compounds are reliant on the strength of the chemical bonds between its constituents; the stronger the bonding between the constituents, the more stable the resulting compound would be.

Complete step by step solution:
We must first learn about the different kinds of bonding provided as an option in the question here.
i) Ionic bonding involves a transfer of an electron, so one atom gains an electron while one atom loses an electron.
ii) A covalent bond involves the sharing of electrons between two atoms. The pair of shared electrons forms a new orbit that extends around the nuclei of both atoms, producing a molecule.
iii) A covalent chemical bond between two atoms that is produced when one atom shares a pair of electrons with another atom lacking such a pair. Also called coordinate covalent bond.

In the picture, we see that \[CuS{O_4}\] is an ionic compound. But when it is hydrated, it forms hydrogen bonding with one of the water molecules and coordinate bonds with the other 4 water molecules hence we can say it has covalent bonding in \[SO_4^{2 - }\].
The bonding in the compound is as follows:
Electrovalent (Ionic interaction between \[C{u^{2 + }}\] & \[SO_4^{2 - }\] ​)
Covalent (with \[SO_4^{2 - }\]​)
Coordinate covalent (\[{H_2}O\] molecules to \[C{u^{2 + }}\] )
Hence, we can conclude that \[CuS{O_4}.5{H_2}O\] has all 3 kinds of bonding.
Thus, Option (C) is the correct answer.

Note: We can easily remove the water of crystallization from hydrated copper (II) sulfate by heating. Condensing the vapor produced in a second test-tube collects the water, we observe the white anhydrous copper (II) sulfate. If it is rehydrated the blue color returns.