QUESTION

# The two diagonally opposite vertices of a square are (6,6) and (0,0). Find the point which lies on X-axis.${\text{A}}{\text{. }}\left( {6,0} \right) \\ {\text{B}}{\text{. }}\left( {0,6} \right) \\ {\text{C}}{\text{. }}\left( {6,6} \right) \\ {\text{D}}{\text{. None}} \\$

${\text{AB = }}\sqrt {{{\left( {6 - x} \right)}^2} + {{\left( {0 - 6} \right)}^2}} \\ 36 = {\left( {6 - x} \right)^2} + 36 \\ 0 = {\left( {6 - x} \right)^2} \\ \therefore x = 6 \\$