
The trigonometric function with a period 7 is:
A. \[\sin \dfrac{\pi }{7}\]
B. \[co\operatorname{s} \dfrac{{2\pi x}}{7}\]
C. \[\tan \dfrac{{2\pi x}}{7}\]
D. \[\cot \dfrac{{2\pi x}}{7}\]
Answer
496.8k+ views
Hint: Here the given question needs to be solved by finding the period for every function, which is equal to seven, here we know the period of the trigonometric function, and from which we can solve further. Period of a trigonometric value means, the angle after which the identity again repeats its value.
Formulae Used: Period of trigonometric function:
\[
\Rightarrow \sin \theta = \cos \theta = 2\pi \\
\Rightarrow \tan \theta = \cot \theta = \pi \\
\]
Complete step by step answer:
Here we know the period for every identity and according to the question we need to solve for the period of seven, so assuming it we will solve further, on solving we get:
For sin function:
\[
\Rightarrow \dfrac{{2\pi }}{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{{2\pi }}{7} \\
\Rightarrow \sin \left( {\dfrac{{2\pi }}{7}} \right) \\
\]
For cosine function:
\[
\Rightarrow \dfrac{{2\pi }}{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{{2\pi }}{7} \\
\Rightarrow \cos \left( {\dfrac{{2\pi }}{7}} \right) \\
\]
For tan function:
\[
\Rightarrow \dfrac{\pi }{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{\pi }{7} \\
\Rightarrow \tan \left( {\dfrac{\pi }{7}} \right) \\
\]
For cot function:
\[
\Rightarrow \dfrac{\pi }{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{\pi }{7} \\
\Rightarrow \cot \left( {\dfrac{\pi }{7}} \right) \\
\]
Here we can see that cosine function is our required answer from the options.
So, the correct answer is “Option B”.
Note: In the given question, we need to remember the period of every trigonometric function, here we know the period of the function, so equate it with the required period as given in the question, so to find the answer. Here the period can be also remembered by the graph of the given function, when the curve reaches back to its past position then the desired range will be the period.
Formulae Used: Period of trigonometric function:
\[
\Rightarrow \sin \theta = \cos \theta = 2\pi \\
\Rightarrow \tan \theta = \cot \theta = \pi \\
\]
Complete step by step answer:
Here we know the period for every identity and according to the question we need to solve for the period of seven, so assuming it we will solve further, on solving we get:
For sin function:
\[
\Rightarrow \dfrac{{2\pi }}{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{{2\pi }}{7} \\
\Rightarrow \sin \left( {\dfrac{{2\pi }}{7}} \right) \\
\]
For cosine function:
\[
\Rightarrow \dfrac{{2\pi }}{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{{2\pi }}{7} \\
\Rightarrow \cos \left( {\dfrac{{2\pi }}{7}} \right) \\
\]
For tan function:
\[
\Rightarrow \dfrac{\pi }{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{\pi }{7} \\
\Rightarrow \tan \left( {\dfrac{\pi }{7}} \right) \\
\]
For cot function:
\[
\Rightarrow \dfrac{\pi }{{\left| a \right|}} = 7 \\
\Rightarrow \left| a \right| = \dfrac{\pi }{7} \\
\Rightarrow \cot \left( {\dfrac{\pi }{7}} \right) \\
\]
Here we can see that cosine function is our required answer from the options.
So, the correct answer is “Option B”.
Note: In the given question, we need to remember the period of every trigonometric function, here we know the period of the function, so equate it with the required period as given in the question, so to find the answer. Here the period can be also remembered by the graph of the given function, when the curve reaches back to its past position then the desired range will be the period.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

