QUESTION

# The total surface area of the given solid figure is –

Hint – Use the formula, total surface area = curved surface area of cone + curved surface area of cylinder + area of base. And then solve.

Now, the curved surface area of cylinder $CS{A_1} = 2\pi rh$.
Curved surface area of cone, $CS{A_2} = \pi rl$.
And, area of base, $B = \pi {r^2}$.
So, now the total surface area of the given figure will be, $A = CS{A_1} + CS{A_2} + B$,
Keeping the values of $CS{A_1} = 2\pi rh$, $CS{A_2} = \pi rl$, $B = \pi {r^2}$in A, we get-
$A = 2\pi rh + \pi rl + \pi {r^2} \\ = \pi r(2h + l + r)sq.units \\$
Hence, the total surface area of the given figure is, $= \pi r(2h + l + r)sq.units$.