
The total surface area of a sphere is $452\dfrac{4}{7}c{{m}^{2}}$. Find the volume of the sphere.
Answer
597.6k+ views
Hint: For solving this problem, first we calculate the radius of the sphere by using the formula for total surface area as the value of total surface area of a sphere is given in the problem statement. Once we obtain the radius of the sphere, we can easily calculate the volume by using the standard formula for volume of sphere.
Complete step-by-step solution -
According to the problem statement, we are given a sphere having a total surface area $452\dfrac{4}{7}c{{m}^{2}}$. The total surface area of a sphere can be expressed as: $4\pi {{r}^{2}}$, where r is the radius of the sphere.
On equating the above values, we get radius as:
\[\begin{align}
& 4\pi {{r}^{2}}=452\dfrac{4}{7} \\
\Rightarrow & 4\times \dfrac{22}{7}\times {{r}^{2}}=\dfrac{3168}{7} \\
\Rightarrow & {{r}^{2}}=\dfrac{3168}{7}\times \dfrac{7}{22\times 4} \\
\Rightarrow & {{r}^{2}}=36 \\
\Rightarrow & r=\sqrt{36} \\
\Rightarrow & r=6cm \\
\end{align}\]
Therefore, the radius of a sphere is 6 cm.
We are required to calculate the volume of the sphere. As we know that the volume of the square can be expressed as: $V=\dfrac{4}{3}\pi {{r}^{3}}$
On putting the value of radius as 6 cm, we get
$\begin{align}
& V=\dfrac{4}{3}\pi {{\left( 6 \right)}^{3}} \\
\Rightarrow & V=\dfrac{4}{3}\times \dfrac{22}{7}\times 6\times 6\times 6 \\
\Rightarrow & V=\dfrac{6336}{7} \\
\Rightarrow & V=905.143c{{m}^{3}} \\
\end{align}$
Therefore, the volume of the sphere is 905.143 ${cm}^{3}$.
Note: Students must remember the formula of total surface area and volume of a sphere for solving this problem. Another important thing in this question is the unit system which is in centimetre. So, the final answer should be left in terms of centimetres.
Complete step-by-step solution -
According to the problem statement, we are given a sphere having a total surface area $452\dfrac{4}{7}c{{m}^{2}}$. The total surface area of a sphere can be expressed as: $4\pi {{r}^{2}}$, where r is the radius of the sphere.
On equating the above values, we get radius as:
\[\begin{align}
& 4\pi {{r}^{2}}=452\dfrac{4}{7} \\
\Rightarrow & 4\times \dfrac{22}{7}\times {{r}^{2}}=\dfrac{3168}{7} \\
\Rightarrow & {{r}^{2}}=\dfrac{3168}{7}\times \dfrac{7}{22\times 4} \\
\Rightarrow & {{r}^{2}}=36 \\
\Rightarrow & r=\sqrt{36} \\
\Rightarrow & r=6cm \\
\end{align}\]
Therefore, the radius of a sphere is 6 cm.
We are required to calculate the volume of the sphere. As we know that the volume of the square can be expressed as: $V=\dfrac{4}{3}\pi {{r}^{3}}$
On putting the value of radius as 6 cm, we get
$\begin{align}
& V=\dfrac{4}{3}\pi {{\left( 6 \right)}^{3}} \\
\Rightarrow & V=\dfrac{4}{3}\times \dfrac{22}{7}\times 6\times 6\times 6 \\
\Rightarrow & V=\dfrac{6336}{7} \\
\Rightarrow & V=905.143c{{m}^{3}} \\
\end{align}$
Therefore, the volume of the sphere is 905.143 ${cm}^{3}$.
Note: Students must remember the formula of total surface area and volume of a sphere for solving this problem. Another important thing in this question is the unit system which is in centimetre. So, the final answer should be left in terms of centimetres.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

